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Excited States with the Hydrogen Bond in the Reaction of Aromatic Dianhydrides with Diamines

机译:芳族二酐与二胺反应中具有氢键的激发态

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Polycondensation of aromatic dianhydrides and diamines is widely used for the synthesis of heat-resistant polymers, polyimides [1]; however, the mechanism of its elementary steps has not been adequately studied. An important problem to be solved concerns the role of the hydrogen bond in proceeding of this reaction. It is expedient to consider this problem in terms of electron excitation in the elementary chemical reaction [2] with the use of specific mechanisms of the electron—proton effect [3, 4]. It is suggested that the interaction of the π-electron systems of the diamine (donor) and dianhydride (electron acceptor) in the excited state through hydrogen bonding leads to a considerable decrease in the energy of the electronic level and its displacement into the thermal energy range (less than 1 eV). The optical charge transfer (CT) transitions for complexes of aromatic diamines and dianhydrides are observed in the visible spectral range 13 000-21000 cm"1 [5]. Recently [2], we put forward the idea that the reaction states have the significance of equilibrium electronically excited states with energies close to the experimental activation energies E_a. For the reaction of pyromellitic dianhydride (PM) with m-phenylenediamine (m-PD), the activation energy is 6—8 kcal/mol [6]. In this context, a problem arises to theoretically estimate the energy of equilibrium excited states and, simultaneously, to determine the role of the electron—proton effect, as a factor of chemical catalysis, due to the interplay of the electron donor—acceptor interaction and hydrogen bond that occurs in electron excitation events.
机译:芳香族二酐和二胺的缩聚反应广泛用于合成耐热聚合物聚酰亚胺[1];但是,其基本步骤的机制尚未得到充分研究。要解决的重要问题涉及氢键在该反应的进行中的作用。考虑到基本化学反应中的电子激发[2],并利用电子-质子效应[3,4]的特定机制,可以方便地考虑这个问题。建议通过氢键处于激发态的二胺(供体)和二酐(电子受体)的π电子体系的相互作用会导致电子能级的能量大大降低,并取代为电子能级范围(小于1 eV)。在可见光谱范围13 000-21000 cm“ 1处观察到芳香族二胺和二酐配合物的光学电荷转移(CT)跃迁。最近[2],我们提出了反应态具有重要意义的想法。平衡电子激发态的能量接近实验活化能E_a。对于均苯四酸二酐(PM)与间苯二胺(m-PD)的反应,活化能为6-8 kcal / mol [6]。在此背景下,由于电子给体-受体相互作用和氢键的相互作用,出现了一个问题,即在理论上估计平衡激发态的能量,并同时确定电子-质子效应作为化学催化因素的作用。在电子激发事件中发生。

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