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首页> 外文期刊>Zeitschrift fur Anorganische und Allgemeine Chemie >Ligand substitution reactions on aquapentachloro- and hexachloroplatinic acid - Synthesis and characterization of tetrachloroplatinum(IV) complexes with heterocyclic N,N donors
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Ligand substitution reactions on aquapentachloro- and hexachloroplatinic acid - Synthesis and characterization of tetrachloroplatinum(IV) complexes with heterocyclic N,N donors

机译:水合五氯和六氯铂酸上的配体取代反应-具有杂环N,N供体的四氯铂(IV)配合物的合成和表征

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摘要

Reactions of aquapentachloroplatinic acid, (H3O)[PtCl5(H2O)].2(18C6).6H(2)O (1) (18C6 = 18-crown-6), and H-2[PtCl6].6H(2)O (2) with heterocyclic N,N donors (2,2'-bipyridine, bpy; 4,4'-di-tert-butyl-2,2'-bipyridine, tBu(2)bpy; 1,10-phenanthroline, phen; 4,7-diphenyl-1,10-phenanthroline, Ph(2)phen; 2,2'-bipyrimidine, bpym) afforded with ligand substitution platinum(IV) complexes [PtCl4(Nboolean ANDN)] (Nboolean ANDN = bpy, 3a; tBu(2)bpy, 3b; Ph(2)phen, 5; bpym, 7) and/or with protonation of N,N donor yielding (R(2)phenH)(2)[PtCl6] (R = H, 4a; Ph, 4b) and (bpymH)(+) (8). With UV irradiation Ph(2)phen and bpym reacted with reduction yielding platinum(II) complexes [PtCl2(Nboolean ANDN)] (Nboolean ANDN = Ph(2)phen, 6; bpym, 9). Identities of all complexes were established by microanalysis as well as by NMR (H-1, C-13, Pt-195) and IR spectroscopic investigations. Molecular structures of [PtCl4(bpym)].MeOH (7) and [PtCl2(Ph(2)phen)] (6) were determined by X-ray diffraction analyses. Differences in reactivity of bpy/bpym and phen ligands are discussed in terms of calculated structures of complexes [PtCl5(Nboolean ANDN)](-) with monodentately bound N,N ligands (Nboolean ANDN = bpy, 10a; phen, 10b; bpym, 10c). [References: 35]
机译:水五氯铂酸,(H3O)[PtCl5(H2O)]。2(18C6).6H(2)O(1)(18C6 = 18-crown-6)和H-2 [PtCl6] .6H(2)的反应O(2)与杂环N,N供体(2,2'-联吡啶,bpy; 4,4'-二叔丁基-2,2'-联吡啶,tBu(2)bpy; 1,10-菲咯啉, phen; 4,7-二苯基-1,10-菲咯啉,Ph(2)phen; 2,2'-bipyrimidine,bpym)提供的配体取代铂(IV)配合物[PtCl4(Nboolean ANDN)](Nboolean ANDN = bpy ,3a; tBu(2)bpy,3b; Ph(2)phen,5; bpym,7)和/或N,N供体的质子化产生(R(2)phenH)(2)[PtCl6](R = H,4a; Ph,4b)和(bpymH)(+)(8)。用紫外线照射,Ph(2)phen和bpym与还原反应生成铂(II)配合物[PtCl2(Nboolean ANDN)](Nboolean ANDN = Ph(2)phen,6; bpym,9)。通过显微分析以及NMR(H-1,C-13,Pt-195)和红外光谱研究确定了所有配合物的身份。通过X射线衍射分析确定[PtCl4(bpym)]。MeOH(7)和[PtCl2(Ph(2)phen)](6)的分子结构。 bpy / bpym和phen配体的反应性差异是根据具有单齿结合N,N配体的复合物[PtCl5(Nboolean ANDN)](-)(Nboolean ANDN = bpy,10a; phen,10b; bpym, 10c)。 [参考:35]

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