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首页> 外文期刊>Zeitschrift fur Anorganische und Allgemeine Chemie >Binuclear nickel(II) complexes with oxalamidinates as bridging ligands: Synthesis and struktures of compounds with planar, tetrahedral, tetragonal-pyramidal, and octahedral coordination [German]
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Binuclear nickel(II) complexes with oxalamidinates as bridging ligands: Synthesis and struktures of compounds with planar, tetrahedral, tetragonal-pyramidal, and octahedral coordination [German]

机译:以草酰二酰胺为桥联配体的双核镍(II)配合物:具有平面,四面体,四角锥体和八面体配位的化合物的合成和结构[德国]

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摘要

Oxalamidines R-1-NH-C(=NR2-C(=NR2)-NH-R-1 react selectively with Ni(acac)(2) under formation of the planar complexes [(acac)Ni(oxalamidinate)Ni(acac)]. Two crystal structures of the binuclear complexes with R = R' = Ph (1) or p-tolyl (2) show that the bridging oxalamidinates bind as bidendate Ligands at each Nickel(II) atom. In contrast, the more sterically demanding fragment (Ph3P)NiBr can only coordinate at sterically less demanding oxalamidinates to form complexes of the type [(Ph3P)NiBr](2)(oxalamidinate) with tetrahedral coordination of Ni-II found by X-ray analyses. Oxalamidines containing additional donor atoms in the side arms react very different, but in each case under formation of binuclear complexes, such as [(acac)(2)Ni](2)(H2E) (8) (with R-1: -(CH2)(3)PPh2, R-2: p-tolyl) in which the oxalamidine acts as bidentate neutral P,N-ligand and the Ni-II atom has an octahedral environment. H2F (with R-1: -(CH2)(3)PPh2; R-2: Mesityl), however, yields the planar complex [(acac)Ni](2)(F) (9) with dianionic oxalamidinate under elimination of acetylacetone. There is no coordination of the donor groups of the side arms in the solid state of complex 9, in contrast to the analogous binuclear complex [(acac)Ni](2)(H) 10 (R-1: -CH2-CH2-2-pyridyl, R-2: Mesityl). In this complex a distorted tetragonal-pyramidal coordination of Ni-II is achieved. 2 reacts with an excess of LiCH3 under elimination of the oxalamidinate to form the cluster compound Li-4(THF)(4)-Ni2Me8 in very good yields, while 9 yields the THF poorer cluster Li-2(THF)(2)Li2Ni2Me8 under similar conditions. [References: 17]
机译:草酰idine R-1-NH-C(= NR2-C(= NR2)-NH-R-1与Ni(acac)(2)选择性反应,形成平面络合物[(acac)Ni(草酰胺基)Ni(acac )]。具有R = R'= Ph(1)或对甲苯基(2)的双核配合物的两个晶体结构表明,桥接的乙二酰胺在每个镍(II)原子上均作为双齿配体结合。 X射线分析发现,高需求片段(Ph3P)NiBr只能与空间上要求不高的草酰胺结合,形成[(Ph3P)NiBr](2)(草酰胺)型与Ni-II的四面体配位的配合物。侧臂中的原子反应非常不同,但在每种情况下都是在双核络合物的形成下形成的,例如[[acac)(2)Ni](2)(H2E)(8)(R-1:-(CH2)( 3)PPh2,R-2:对甲苯基),其中草al啶充当双齿中性P,N-配体,Ni-II原子具有八面体环境.H2F(R-1:-(CH2)(3) PPh2; R-2:Mesityl),但生成平面络合物[(acac)Ni](2 )(F)(9)在消除乙酰丙酮的条件下,用二草酰草酰胺酸根。与类似的双核络合物[(acac)Ni](2)(H)10(R-1:-CH2-CH2- 2-吡啶基,R-2:甲磺酰基)。在这种络合物中,Ni-II的四方金字塔形配位得以实现。 2在消除草酰胺基化物的情况下与过量的LiCH3反应以非常好的收率形成簇化合物Li-4(THF)(4)-Ni2Me8,而9则得到THF较差的簇Li-2(THF)(2)Li2Ni2Me8在类似条件下。 [参考:17]

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