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Factorization formulae on counting zeros of diagonal equations over finite fields

机译:有限域对角方程零点的因式分解公式

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摘要

Let N be the number of solutions (u(1), . . . , u(n)) of the equation a(1)u(1)(d1) + (.) (.) (.) + a(n)u(n)(dn) = 0 over the. nite. eld F-q, and let I be the number of solutions of the equation Sigma(n)(i=1) x(i)/d(i) equivalent to 0 (mod 1), 1 <= x(i) <= d(i) - 1. If I > 0, let L be the least integer represented by Sigma(n)(i=1) x(i)/d(i), 1 <= x(i) <= d(i) - 1. I and L play important roles in estimating N. Based on a partition of {d(1), . . . , d(n)}, we obtain the factorizations of I, L and N, respectively. All these factorizations can simplify the corresponding calculations in most cases or give the explicit formulae for N in some special cases.
机译:令N为方程a(1)u(1)(d1)+(。)(。)(。)+ a(n)的解数(u(1),...,u(n)) )u(n)(dn)= 0。天黑。场Fq,令我为等式Sigma(n)(i = 1)x(i)/ d(i)的解数等于0(mod 1),1 <= x(i)<= d (i)-1.如果I> 0,则令L为由Sigma(n)(i = 1)x(i)/ d(i)表示的最小整数,1 <= x(i)<= d(i )-1. I和L在估算N中起着重要作用。基于{d(1),的分区。 。 。 ,d(n)},我们分别获得I,L和N的因式分解。所有这些分解都可以在大多数情况下简化相应的计算,或者在某些特殊情况下为N提供明确的公式。

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