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Syntheses and crystal structures of four cyanide-bridged trinuclear iron(III)-copper(II)-iron(III) complexes exhibiting abnormal antiferromagnetic coupling

机译:表现出反铁磁耦合的四种氰基桥联三核铁(III)-铜(II)-铁(III)配合物的合成和晶体结构

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Four heterobimetallic trinuclear Fe-D-Cu-II-Fe-D complexes [Cu(cyclam)][Fe(bpb)(CN)(2)](2)center dot 4H(2)O (1), [Cu(cyclam)][Fe(bpClb)(CN)(2)](2)center dot 4H(2)O (2), [Cu(cyclam)][Fe(bpmb)(CN)(2)](2)center dot 4H(2)O (3) and [Cu(cyclam)][Fe(bpdmb)- (CN)(2)](2)center dot H2O (4) (cyclam = 1,4,8,11-tetraazacyclotetradecane, bpb(2-) = 1,2-bis(pyridine-2-carboxamido), bpClb(2-) = 1,2-bis(pyridine-2-carboxamido)-4-chloro-benzenate, bpmb(2-) = 1,2-bis(pyridine-2-carboxamido)-4-methyl-benzenate, bpdmb(2-) = 1,2-bis(pyridine-2-carboxamido)-4,5-dimethyl-benzenate) have been synthesized based on cyanide-containing building blocks [Fe(L)CN2](-) (L = bpb(2-), bpClb(2-), bpmb(2-) and bpdmb(2-)) and [Cu(cyclam)](2+). Their structures and magnetic properties were investigated. The single-crystal X-ray diffraction analyses reveal that they are all neutral trinuclear sandwich-like structures. Magnetic investigations show that they are all abnormal antiferromagnetic, with J = -0.95 cm(-1) for 1, -0.70 cm(-1) for 2, -0.93 cm(-1) for 3 and -0.85 cm(-1) for 4 based on the Hamiltonian Acurrency sign = -2 JAe (Cu)(Ae (Fe(1)) + Ae (Fe(2))). The abnormal antiferromagnetic coupling between Fe(III) and Cu(II) in the four complexes can be attributed to the small Cu-Na parts per thousand C bond angles.
机译:四个杂双金属三核Fe-D-Cu-II-Fe-D络合物[Cu(cyclam)] [Fe(bpb)(CN)(2)](2)中心点4H(2)O(1),[Cu( Cyclam)] [Fe(bpClb)(CN)(2)](2)中心点4H(2)O(2),[Cu(cyclam)] [Fe(bpmb)(CN)(2)](2)中心点4H(2)O(3)和[Cu(cyclam)] [Fe(bpdmb)-(CN)(2)](2)中心点H2O(4)(cyclam = 1,4,8,11-四氮环十四烷,bpb(2-)= 1,2-双(吡啶-2-甲酰胺基),bpClb(2-)= 1,2-双(吡啶-2-甲酰胺基)-4-氯苯甲酸酯,bpmb(2- )= 1,2-双(吡啶-2-甲酰胺基)-4-甲基苯甲酸酯,bpdmb(2-)= 1,2-双(吡啶-2-甲酰胺基)-4,5-二甲基苯甲酸酯)合成基于含氰化物的结构单元[Fe(L)CN2](-)(L = bpb(2-),bpClb(2-),bpmb(2-)和bpdmb(2-))和[Cu(cyclam )](2+)。研究了它们的结构和磁性能。 X射线单晶衍射分析表明它们都是中性的三核三明治状结构。磁研究表明它们都是反铁磁异常,其中J = -0.95 cm(-1)for 1,-0.70 cm(-1)for 2,-0.93 cm(-1)for 3和-0.85 cm(-1)基于Hamiltonian并发符号= -2 JAe(Cu)(Ae(Fe(1))+ Ae(Fe(2)))得出4。四个配合物中的Fe(III)和Cu(II)之间反铁磁耦合异常可归因于每千个C键角的Cu-Na小部分。

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