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首页> 外文期刊>Tetrahedron >Convenient Syntheses of 9-[4-Hydroxy-3-(hydroxymethyl_butyl]-guanine (Penciclovir) and 9-[4-Acetoxy-3-(acetoxymethyl)butyl]-2-amino-9H-purine (Famciclovir)
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Convenient Syntheses of 9-[4-Hydroxy-3-(hydroxymethyl_butyl]-guanine (Penciclovir) and 9-[4-Acetoxy-3-(acetoxymethyl)butyl]-2-amino-9H-purine (Famciclovir)

机译:9- [4-羟基-3-(羟甲基_丁基]-鸟嘌呤(喷昔洛韦)和9- [4-乙酰氧基-3-(乙酰氧基甲基)丁基] -2-氨基-9H-嘌呤(泛昔洛韦)的便捷合成

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摘要

Guanine 11 was converted, in a one pot reaction, into 2-amino-6-[(4-chlorophenyl)sulfanyl]purine 9a in 88% isolated yield. 4-Acetoxy-3-(acetoxymethyl)butanol 23 was prepared from 2-chloroethanol in five steps and in 46% overall yield. The mesylate ester of compound 23 reacted with 9a in the presence of potassium carbonate with a high degree of regioselectivity (89%) to give the N-9 alkylated product 26 which was isolated in 80% yield. Acidic hydrolysis of the latter compound 26 gave penciclovir 4 in virtually quantitative yield. Penciclovir 4 and famciclovir 5 were prepared from 2-amino-6-[(4-chlorophenyl)sulfanyl]purine 9a in four and five steps, respectively, by procedures involving initial alkylation with 1,2-dibromoethane. The overall yields obtained were 65 and ca. 60%, respectively.
机译:在一个罐反应中,鸟嘌呤11以88%的分离产率转化为2-氨基-6-[(4-氯苯基)硫烷基]嘌呤9a。由2-氯乙醇分五个步骤制备4-乙酰氧基-3-(乙酰氧基甲基)丁醇23,总产率为46%。在碳酸钾存在下,化合物23的甲磺酸酯与9a反应,具有高度的区域选择性(89%),得到N-9烷基化产物26,其以80%的收率分离。后一种化合物26的酸性水解以实际上定量的产率得到了喷昔洛韦4。通过2-氨基-6-[(4-氯苯基)硫烷基]嘌呤9a分别通过涉及用1,2-二溴乙烷进行初始烷基化的步骤,由2-氨基-6-[(4-氯苯基)硫烷基]嘌呤9a制备喷昔洛韦4和泛昔洛韦5。所获得的总产量为65。 60%。

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