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首页> 外文期刊>Proceedings of the Royal Society. Mathematical, physical and engineering sciences >Point vortex equilibria and optimal packings of circles on a sphere
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Point vortex equilibria and optimal packings of circles on a sphere

机译:点涡平衡和球体上的最佳圆堆积

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We answer the question of whether optimal packings of circles on a sphere are equilibrium solutions to the logarithmic particle interaction problem for values of N =3-12 and 24, the only values of N for which the optimal packing problem (also known as the Tammes problem) has rigorously known solutions. We also address the cases N =13-23 where optimal packing solutions have been computed, but not proven analytically. As in Jamaloodeen & Newton (Jamaloodeen & Newton 2006 Proc. R. Soc. Lond. Ser. A 462, 3277-3299. (doi:10.1098/rspa.2006.1731)), a logarithmic, or point vortex equilibrium is determined by formulating the problem as the one in linear algebra, A→Γ =0, where A is a N(N - 1)/2 × N non-normal configuration matrix obtained by requiring that all interparticle distances remain constant. If A has a kernel, the strength vector →Γ ?N is then determined as a right-singular vector associated with the zero singular value, or a vector that lies in the nullspace of A where the kernel is multi-dimensional. First we determine if the known optimal packing solution for a given value of N has a configuration matrix A with a non-empty nullspace. The answer is yes for N =3-9, 11-14, 16 and no for N =10, 15, 17-24. We then determine a basis set for the nullspace of A associated with the optimally packed state, answer the question of whether N-equal strength particles, →Γ =(1, 1, 1, ?, 1)T, form an equilibrium for this configuration, and describe what is special about the icosahedral configuration from this point of view. We also find new equilibria by implementing two versions of a random walk algorithm. First, we cluster sub-groups of particles into patterns during the packing process, and grow a packed state using a version of the yin-yang algorithm of Longuet-Higgins (Longuet-Higgins 2008 Proc. R. Soc. A (doi:10.1098/rspa.2008.0219)). We also implement a version of our Brownian ratchet algorithm to find new equilibria near the optimally packed state for N =10, 15, 17-24.
机译:我们回答以下问题:对于N = 3-12和24的值,N的唯一值是否是对数粒子相互作用问题的平衡解,这是N的唯一值,即唯一的最优堆积问题(也称为Tammes)问题)具有严格已知的解决方案。我们还解决了N = 13-23的情况,其中已经计算了最佳包装解决方案,但没有经过分析证明。就像在Jamaloodeen&Newton(Jamaloodeen&Newton 2006 Proc.R.Soc.Lond.Ser.A 462,3277-3299。(doi:10.1098 / rspa.2006.1731))中一样,对数或点涡旋平衡通过公式线性代数中的一个问题,即A→Γ= 0,其中A是通过要求所有粒子间距离保持恒定而获得的N(N-1)/ 2×N非正态配置矩阵。如果A有一个核,则将强度向量→ΓΔN确定为与零奇异值关联的右奇异向量,或位于A的零空间的向量,其中核是多维的。首先,我们确定给定N值的已知最佳打包解是否具有带非空零空间的配置矩阵A。对于N = 3-9、11-14、16,答案为是,对于N = 10、15、17-24,答案为否。然后,我们确定与最佳堆积状态相关的A的零空间的基础集,回答以下问题:N等强度粒子→Γ=(1,1,1,?,1)T是否为此形成平衡配置,并从这个角度描述二十面体配置的特殊之处。通过实现两个版本的随机游走算法,我们也找到了新的平衡点。首先,我们在包装过程中将粒子的子组聚集成图案,并使用Longuet-Higgins的阴阳算法(Longuet-Higgins 2008 Proc.R.Soc.A(doi:10.1098 /rspa.2008.0219)。我们还实现了布朗棘轮算法的一种版本,可以在N = 10、15、17-24的最佳压缩状态附近找到新的平衡点。

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