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Partial synthesis of 14α-hydroxy-5α-cholestan-3β-yl acetate

机译:14α-羟基-5α-胆甾醇-3β-乙酸乙烯酯的部分合成

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摘要

A convenient synthesis (in seven steps) of the 14α-hydroxy-5α-cholestan-3β-yl acetate (8, Scheme 2) is described. The synthesis starts from cholesteryl acetate (1) and involves the following transformations: (i) bromination/dehydrobromination of cholesteryl acetate (1); (ii) partial hydrogenation of the △~5-bond in the obtained 7-dehydrocholesteryl acetate (2); (iii) migration of the △~7-double bond in the thus formed compound 3 to the △~8(14)-position; (iv) isomerisation of the △~8(14)-unsaturated product 4 to the △~14-analogue 5 (v) epoxidation of the △~14-bond in 5; (vi) lithium aluminium hydride reduction of the 14α, 15α-epoxide 6; and (vii) partial acetylation of the 3β-hydroxyl function in the obtained diol 7 producing the final product 8. The total yield of the synthesis is ca. 18/100.
机译:描述了14α-羟基-5α-胆甾醇-3β-乙酸乙烯酯的方便的合成(七个步骤)(8,方案2)。合成从乙酸胆固醇酯(1)开始,并且涉及以下转化:(i)乙酸胆固醇酯(1)的溴化/脱氢溴化; (ii)将所得的7-脱氢胆固醇乙酸酯(2)中的△〜5-键部分氢化。 (iii)如此形成的化合物3中的△〜​​7-双键向△〜8(14)-位的迁移; (iv)将△〜8(14)-不饱和产物4异构化为△〜14-类似物5(v)△5中的△〜14键的环氧化; (vi)将氢化铝锂还原成14α,15α-环氧化物6; (vii)所得二醇7中3β-羟基官能团的部分乙酰化,生成最终产物8。 18/100。

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