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Derandomized Parallel Repetition Theorems for Free Games

机译:免费游戏的非随机并行重复定理

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摘要

Raz’s parallel repetition theorem (SIAM J Comput 27(3):763–803, 1998) together with improvements of Holenstein (STOC, pp 411–419, 2007) shows that for any two-prover one-round game with value at most ({1- epsilon}) (for ({epsilon leq 1/2})), the value of the game repeated n times in parallel on independent inputs is at most ({(1- epsilon)^{Omega(frac{epsilon^2 n}{ell})}}), where ℓ is the answer length of the game. For free games (which are games in which the inputs to the two players are uniform and independent), the constant 2 can be replaced with 1 by a result of Barak et al. (APPROX-RANDOM, pp 352–365, 2009). Consequently, ({n=O(frac{t ell}{epsilon})}) repetitions suffice to reduce the value of a free game from ({1- epsilon}) to ({(1- epsilon)^t}), and denoting the input length of the game by m, it follows that ({nm=O(frac{t ell m}{epsilon})}) random bits can be used to prepare n independent inputs for the parallel repetition game.
机译:拉兹(Raz)的平行重复定理(SIAM J Comput 27(3):763–803,1998)以及Holenstein(STOC,pp 411–419,2007)的改进表明,对于任何两个证明者,一轮游戏最多具有价值( {1- epsilon})(对于({epsilon leq 1/2})),在独立输入上并行重复n次的游戏值最多为({(1- epsilon)^ {Omega(frac {epsilon ^ 2 n} {ell})}}),其中ℓ是游戏的答案长度。对于免费游戏(这是两个玩家的输入是统一且独立的游戏),常数2可以用Barak等的结果替换为1。 (APPROX-RANDOM,第352–365页,2009年)。因此,({n = O(frac {tell} {epsilon})})重复就足以将免费游戏的价值从({1-epsilon})减少到({(1-epsilon)^ t}),并且用m表示游戏的输入长度,可以得出({nm = O(frac {tell m} {epsilon})})随机比特可以用来为并行重复游戏准备n个独立的输入。

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