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Method to Compute the Enthalpy Difference of a Liquid Stream in the Absence of an EoS-based Function

机译:缺少基于EoS的函数时液体流的焓差的计算方法

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摘要

This paper derives equations for the calculation of enthalpy and enthalpy difference as a function of both temperature and pressure that can be used when a full equation of state description is not available for a liquid. A result is the inclusion of the "volume expansivity ", usually a small effect, but missing in most other literature. In the end, the equations are easy to implement in the analysis of data or predictions of component performance. This paper also displays the relative importance of pressure drop to change in temperature when computing heat transfer rates. For example, a pressure drop of 140 kPa (20 psid) accounts for 1% of the enthalpy difference for a stream of water undergoing a 2.8℃δ (5℉δ) change in temperature. Although this might not appear to be significant, it can be important when computing system energy balance closures for performance standards that call for tight energy balance closure, ±3% being typical.
机译:本文推导出用于计算焓和焓差的方程,该方程是温度和压力的函数,当无法使用液体的完整状态描述方程时,可以使用该方程。结果是包含了“体积膨胀性”,通常效果很小,但是在大多数其他文献中却没有。最后,这些方程很容易在数据分析或组件性能预测中实现。本文还显示了在计算传热速率时,压降对温度变化的相对重要性。例如,对于温度经历2.8℃δ(5℉δ)变化的水流,140 kPa(20 psid)的压降占焓差的1%。尽管这似乎并不重要,但在为性能标准计算系统能量平衡关闭要求严格的能量平衡关闭(通常为±3%)时,这一点可能很重要。

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  • 来源
    《ASHRAE Transactions 》 |2013年第2期| 322-329| 共8页
  • 作者

    K.J. Schultz;

  • 作者单位

    Senior Development Engineer for Trane, a division of Ingersoll Rand, La Crosse, WI, USA;

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  • 正文语种 eng
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