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Binuclear Palladium(I) and Palladium(II) Complexes of ortho-Functionalized 13-Bis(aryl)triazenido Ligands

机译:邻官能化的13-双(芳基)三氮杂多配体的双核钯(I)和钯(II)配合物

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摘要

Three new bis(aryl)triazene ligands, Ar-NNNH-Ar′ [Ar=Ar′=o-C6H4-CO2Me (>2); Ar=o-C6H4-CO2Me, Ar′=p-C6H4-CH3 (>3); Ar=o-C6H4-SMe, Ar′=p-C6H4-CH3) (>4)], have been synthesized. Reaction of >1–4 with PdCl2(NCCH3)2 in the presence of a base afforded a series of binuclear diamagnetic palladium complexes. In these reactions, ligands >1–3 afforded the palladium(I) complexes [PdI(o-MeO2C-C6H4-NNN-o-C6H4-CO2Me)]2 (>5, monoclinic, space group P21/c, a=8.6070(10) Å, b=14.3220(10) Å, c=12.7310(10) Å, β=100.2950(10)°, Z=2), [PdI(o-MeO-C6H4-NNN-o-C6H4-OMe)]2 (>6, triclinic, space group P1̅. a=6.6288(5) Å, b=10.2631(10) Å, c=11.0246(11) Å, α=85.579(6)°, β=80.885(6)°, γ=74.607(6)°, Z=1), and [PdI(o-MeO2C-C6H4-NNN-p-C6H4-CH3)]2 (>7, tetragonal, space group I 41/a, a=20.866(3) Å, b=20.866(3) Å, c=13.156(2) Å, Z=8). In contrast, reaction of ligand >4 with PdCl2(NCCH3)2 resulted in the formation of a palladium(II) dimer, [PdII(o-MeS-C6H4-NNN-p-C6H4-CH3)Cl]2 (>8, orthorhombic, space group P21212, a=10.4058(5) Å, b=16.2488(8) Å, c=9.9500(5) Å, Z=2).
机译:三个新的双(芳基)三氮烯配体Ar-NNNH-Ar'[Ar = Ar'= o-C6H4-CO2Me(> 2 ); Ar = o-C6H4-CO2Me,Ar'= p-C6H4-CH3(> 3 );合成了Ar = o-C6H4-SMe,Ar'= p-C6H4-CH3)(> 4 )]。在碱的存在下> 1-4 与PdCl2(NCCH3) 2 的反应提供了一系列双核抗磁性钯配合物。在这些反应中,配体> 1-3 提供了钯(I)配合物[Pd I (o-MeO 2 CC 6 < / sub> H 4 -NNN-oC 6 H 4 -CO 2 Me)] 2 (> 5 ,单斜,空间群P2 1 /c,a=8.6070(10)Å,b = 14.3220(10)Å,c = 12.7310( 10)Å,β= 100.2950(10)°,Z = 2),[Pd I (o-MeO-C 6 H 4 -NNN-oC 6 H 4 -OMe)] 2 (> 6 ,斜线,空间群P <数学> 1 ̅ 。a = 6.6288(5)Å,b = 10.2631(10)Å, c = 11.0246(11)Å,α= 85.579(6)°,β= 80.885(6)°,γ= 74.607(6)°,Z = 1)和[Pd I (< em> o -MeO 2 CC 6 H 4 -NNN- p -C 6 H 4 -CH 3 )] 2 (> 7 ,四边形,空间群I 41 / a, a = 20.866(3)Å, b = 20.866(3)Å, c = 13.156(2)Å,Z = 8)。相反,配体> 4 与PdCl 2 (NCCH 3 2 的反应导致钯的形成(II)二聚体,[Pd II o -MeS-C 6 H 4 -NNN- p -C 6 H 4 -CH 3 )Cl] 2 (> 8 正交空间群P2 1 2 1 2, a = 10.4058(5)Å, b < /em>=16.2488(8)Å, c = 9.9500(5)Å,Z = 2)。

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