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A simple decision analytic solution to the comparison of two binary diagnostic tests

机译:两个二元诊断测试比较的简单决策解

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摘要

One of the most basic biostatistical problems is the comparison of two binary diagnostic tests. Commonly, one test will have greater sensitivity and the other greater specificity. In this case, the choice of the optimal test generally requires a qualitative judgment as to whether gains in sensitivity are offset by losses in specificity. Here we propose a simple decision-analytic solution in which sensitivity and specificity are weighted by an intuitive parameter, the threshold probability of disease at which a patient will opt for treatment. This gives a net benefit that can be used to determine which of two diagnostic tests will give better clinical results at a given threshold probability, and whether either is superior to the strategy of assuming that all or no patients have disease. We derive a simple formula for the relative diagnostic value, which is the difference in sensitivities of two tests divided by the difference in the specificities. We show that multiplying relative diagnostic value by the odds at the prevalence gives the odds of the threshold probability below which the more sensitive test is preferable, and above which the more specific test should be chosen. The methodology is easily extended to incorporate combination of tests, and the risk or side-effects of a test.
机译:最基本的生物统计学问题之一是两个二进制诊断测试的比较。通常,一种测试将具有更高的灵敏度,而另一种则具有更高的特异性。在这种情况下,最佳测试的选择通常需要对灵敏度的提高是否被特​​异性的降低所抵消的定性判断。在这里,我们提出了一种简单的决策分析解决方案,其中敏感性和特异性由直观参数(患者选择治疗的疾病阈值概率)加权。这提供了一个净收益,可用于确定在给定的阈值概率下两个诊断测试中的哪一个将提供更好的临床结果,以及是否优于假定所有患者都患有疾病的策略。我们得出一个相对诊断值的简单公式,即两个测试的灵敏度差异除以特异性差异。我们表明,将相对诊断值乘以患病率的几率可得出阈值概率的几率,低于此阈值的可能性最好采用更敏感的测试,而高于该阈值的可能性则应选择更具体的测试。该方法很容易扩展以结合测试的组合以及测试的风险或副作用。

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