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Genome aliquoting with double cut and join

机译:基因组等调分用双切割并加入

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Background: The genome aliquoting probem is, given an observed genome A with n copies of each gene, presumed to descend from an n-way polyploidization event from an ordinary diploid genome 8, followed by a history of chromosomal rearrangements, to reconstruct the identity of the original genome 6'. The idea is to construct 8', containing exactly one copy of each gene, so as to minimize the number of rearrangements d(A, 6 8 ...6') necessary to convert the observed genome 8' 8' ...8' into A.Results: Inthis paper we make the first attempt to define and solve the genome aliquoting problem. We present a heuristic algorithm for the problem as well the data from our experiments demonstrating its validity.Conclusion: The heuristic performs well, consistently giving a non-trivial result. The question as to the existence or non-existence of an exact solution to this problem remains open.
机译:背景:给出了在每个基因的N拷贝的观察到的基因组A中等调等,假定从普通二倍体基因组8中下降,然后是染色体重排的历史,重建身份 原始基因组6'。 该想法是构建8',包含每个基因的一份副本,以最小化转换观察到的Genome 8'8'8所需的重排(A,6 8 ... 6')的次数 '进入A.Results:Inthis Paper我们首次尝试定义和解决等分试样问题的基因组。 我们为问题提出了一种启发式算法,以及我们实验的数据展示其有效性。结论:启发式表现良好,一贯给出非琐碎的结果。 对此问题确切解决方案的存在或不存在的问题仍然是开放的。

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