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Inoculation strategies for victims of viruses and the sum-of-squares partition problem

机译:病毒受害者的接种策略和平方和分区问题

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We propose a simple game for modeling containment of the spread of viruses in a graph of n nodes. Each node must choose to either install anti-virus software at some known cost C, or risk infection and a loss L if a virus that starts at a random initial point in the graph can reach it without being stopped by some intermediate node. The goal of individual nodes is to minimize their individual expected cost. We prove many game theoretic properties of the model, including an easily applied characterization of Nash equilibria, culminating in our showing that allowing selfish users to choose Nash equilibrium strategies is highly undesirable, because the price of anarchy is an unacceptable Θ(n) in the worst case. This shows in particular that a centralized solution can give a much better total cost than an equilibrium solution. Though it is NP-hard to compute such a social optimum, we show that the problem can be reduced to a previously unconsidered combinatorial problem that we call the sum-of-squares partition problem. Using a greedy algorithm based on sparse cuts, we show that this problem can be approximated to within a factor of O(log2 n), giving the same approximation ratio for the inoculation game.
机译:我们提出了一个简单的游戏,用于对 n 节点图中的病毒传播进行建模。每个节点必须选择以某些已知成本 C 安装防病毒软件,否则,如果病毒在Internet中的随机初始位置启动,则有感染风险和损失 L 的风险。图可以到达它而不会被某个中间节点停止。单个节点的目标是最大程度地减少其单个预期成本。我们证明了该模型的许多博弈论性质,包括易于应用的纳什均衡的刻画,最终证明了让自私的用户选择纳什均衡策略是非常不可取的,因为无政府状态的价格是不可接受的Θ( n )。这特别表明,与均衡解决方案相比,集中式解决方案可以提供更好的总成本。尽管很难计算出这样的社会最优值,但是我们证明,该问题可以简化为先前未考虑的组合问题,我们称之为平方和分区问题。 / B>使用基于稀疏割的贪婪算法,我们证明此问题可以近似地在 O (log 2 n ),从而为接种游戏提供相同的近似率。

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