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(RARE EARTH)-IRON-BORON MAGNETIC ALLOY AND ITS PRODUCTION AND BOND MAGNET USING THE (RARE EARTH)-IRON-BORON MAGNETIC ALLOY

机译:(稀土)-铁-硼磁性合金及其使用(稀土)-铁-硼磁性合金的生产和粘结磁铁

摘要

PROBLEM TO BE SOLVED: To obtain high residual magnetic flux density and high coercive force by specifying the composition of elements and the constitution of alloy structure, respectively. ;SOLUTION: This alloy has a composition represented by the formula, RxFe100-x-y-z-wCOyMzBw [where R is one or more kinds among five rare earth elements such as Nd, M is one or more kinds among 14 elements such as Ti, and 5≤x≤10, 0≤y≤9.0, 0.1≤z≤5, 2≤w≤7, 9≤(x+w), and 5(y+z) are satisfied]. Moreover, this alloy has an alloy structure in which soft magnetic crystalline phases, containing solid solution of αFe, bccFe, and the above M, and hard magnetic crystalline phases, composed of Nb2Fe14B1 type tetragonal system crystal, are precipitated in soft magnetic amorphous phases, respectively. Further, by regulating the area ratios of these amorphous phases and crystalline phases to respectively prescribed values, residual magnetic flux density as high as ≥10kG and coercive force as high as ≥3.5kOe can be obtained, and, as a result the alloy, having high maximum energy product and excellent in rust- preventing property, can be obtained.;COPYRIGHT: (C)1998,JPO
机译:解决的问题:通过分别指定元素的组成和合金结构的组成,以获得高的剩余磁通密度和高的矫顽力。 ;解决方案:该合金的成分由下式表示:R x Fe 100-xyzw CO y M z B w [其中,R是Nd等5种稀土元素中的一种或多种,​​M是Ti等14种元素中的一种或多种,​​且5≤x≤10,0≤y ≤9.0、0.1≤z≤5、2≤w≤7、9≤(x + w),5 <(y + z)。此外,该合金具有由αFe,bccFe和上述M的固溶体构成的软磁性结晶相,由Nb 2 Fe 14构成的硬磁性结晶相的合金结构。 B 1 型四方晶系晶体分别在软磁性非晶相中析出。此外,通过将这些非晶相和结晶相的面积比分别调节为规定值,可获得大于或等于10kG的剩余磁通密度和大于或等于3.5kOe的矫顽力,结果合金具有获得了最高的最大能量乘积,并且具有优异的防锈性能。;版权所有:(C)1998,日本特许厅

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