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INORGANIC POLYMER MATERIAL USING ALUMINUM AND SILICON AS BASE MATERIAL

机译:以铝和硅为基础的无机高分子材料

摘要

PROBLEM TO BE SOLVED: To obtain the viscosity higher than that of a fiber phase by forming a spindle shaped polymeric aluminosilicate having specific length, max. width and ratio (length)/(the max. width). ;SOLUTION: The spindle shaped polymeric aluminosilicate having 10-100 μm length L, 2-20 μm max. width T and the ratio L/T of 2-10 and expressed by the formula; AlxSiyOz (x/y=1-3, z represents 1-10) is provided. The aluminosilicate is formed by adjusting an alkali aq. solution of a hydrolyzable Al compound such as AlCl3 and a hydrolyzable Si compound such as Si(OCH3)4 to pH 4-6.5 while keeping the Al concentration to 5×10-4-10-2M and the molar ratio Al/Si to 1-3, allowing the resultant mixture to react in the presence of a silanol group and holding for a prescribed time at 100°C. The solution is concentrated until the concentration of Al+Si reaches about 1.5 g/L, forming into two phases by decantation and the aluminosilicate containing ≥90 wt.% spindle shaped one is obtained from the upper phase.;COPYRIGHT: (C)1999,JPO
机译:解决的问题:通过形成具有特定长度(最大)的纺锤形聚合铝硅酸盐来获得高于纤维相的粘度。宽度和比率(长度)/(最大宽度)。 ;解决方案:纺锤形聚合铝硅酸盐的长度L为10-100μm,最大2-20μm。宽度T和L / T之比为2-10,由公式表示;提供了Al x Si y O z (x / y = 1-3,z表示1-10)。铝硅酸盐是通过调节碱水溶液而形成的。将可水解Al化合物如AlCl 3 和可水解Si化合物如Si(OCH 3 4 的溶液溶解至pH 4-6.5保持Al浓度为5×10 -4 -10 -2 M,Al / Si摩尔比为1-3,使所得混合物在存在下反应硅烷醇基团并在<100℃下保持规定时间。浓缩溶液直到Al + Si的浓度达到约1.5 g / L,通过倾析形成两相,并从上层相中获得≥90 wt。%纺锤形的铝硅酸盐。版权所有:(C)1999 ,日本特许厅

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