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Method of forming superconducting magnets using stacked LTS/HTS coated conductor
Method of forming superconducting magnets using stacked LTS/HTS coated conductor
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机译:使用堆叠的LTS / HTS涂层导体形成超导磁体的方法
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摘要
A method of forming magnets using stacked superconducting films-disks of coated conductor is described. The superconducting material may be either from the oxide high temperature superconducting (HTS) class or the metallic/inter-metallic low temperature superconducting (LTS) class. An LTS metallic or inter-metallic compound can include Nb, Va, Ti, Hg, Pb, NbTi, Nb3Sn, Nb3Al, etc. or the more recently discover MgB2. An oxide superconductor refers to the RE-Ba2Cu3Ox compound, wherein RE=Y, Nd, La, Sm, Eu, Gd, Dy, Ho, Er, Tm, Yb, Lu; the Bi2Sr2CaCu2Ox, the (Bi, Pb)2Sr2CaCu2Ox, Bi2Sr2Ca2Cu3Ox or (Bi, Pb)2Sr2Ca2Cu3Ox compound; the Tl2Ca1.5BaCu2Ox or Tl2Ca2Ba2Cu3Ox compound; or a compound involving substitution such as the Nd1+xBa2−xCu3Ox compounds.
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机译:描述了一种使用涂覆的导体的堆叠的超导膜-盘形成磁体的方法。超导材料可以是氧化物高温超导(HTS)类别的,也可以是金属/金属间低温超导(LTS)类别的。 LTS金属或金属间化合物可以包括Nb,Va,Ti,Hg,Pb,NbTi,Nb 3 Sub> Sn,Nb 3 Sub> Al等发现MgB 2 Sub>。氧化物超导体是指RE-Ba 2 Sub> Cu 3 Sub> O x Sub>的化合物,其中RE = Y,Nd,La,Sm,Eu, Gd,Dy,Ho,Er,Tm,Yb,Lu; Bi 2 Sub> Sr 2 Sub> CaCu 2 Sub> O x Sub>,(Bi,Pb) 2 Sub> Sr 2 Sub> CaCu 2 Sub> O x Sub>,Bi 2 Sub> Sr 2 Sub> Ca < Sub> 2 Sub> Cu 3 Sub> O x Sub>或(Bi,Pb) 2 Sub> Sr 2 Sub> Ca < Sub> 2 Sub> Cu 3 Sub> O x Sub>化合物; Tl 2 Sub> Ca 1.5 Sub> BaCu 2 Sub> O x Sub>或Tl 2 Sub> Ca 2 Sub> Ba 2 Sub> Cu 3 Sub> O x Sub>化合物;或涉及取代的化合物,例如Nd 1 + x Sub> Ba 2-x Sub> Cu 3 Sub> O x Sub>化合物。
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