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Method and system of spatial localization by luminous markers for any environment (Machine-translation by Google Translate, not legally binding)

机译:在任何环境下通过发光标记进行空间定位的方法和系统(通过Google翻译进行机器翻译,没有法律约束力)

摘要

Method and system of spatial localization of an objective (10) in a three-dimensional environment (11) comprising at least one luminous marker comprising: - a stereo camera (12) for capturing a first image frame at a current time and a second image frame at a previous instant; - an angle measuring device (13) for obtaining an angle of rotation of the lens (10); - a signal processor (14) with access to a memory (15) that stores among others a radius of the at least one marker detected at a current time instant n and at a previous time instant N-1 configured to calculate some coordinates (xi, andi) of the target (10) at a time instant i as follows: - if the angle of rotation at the current time instant and at the previous time instant are different, (xn, andn) = (xn -1, andn-1); - if the two image frames are equal, (x {sub, n, andn) = (xn-1, andn -1); - in another case: - if the radii are equal and there are several markers, (xn, andn) are calculated by triangulation using both image frames; - if the radii are different and there are several markers, (xn, andn) are calculated by triangulation using a single image frame; - if the radii are different and there is a single marker, (xn, andn) are calculated by stereo geometry; - if the radii are the same and there is a single marker, (xn, andn) are calculated using image coordinates of the marker at the current time and the previous one. (Machine-translation by Google Translate, not legally binding)
机译:在包括至少一个发光标记的三维环境(11)中对物镜(10)进行空间定位的方法和系统,包括:-立体摄像机(12),用于在当前时间捕获第一图像帧和第二图像在前一瞬间进行构图; -用于获得透镜(10)的旋转角度的角度测量装置(13); -可以访问存储器(15)的信号处理器(14),该存储器尤其存储在当前时刻n和在先前时刻N-1检测到的至少一个标记的半径,该半径被配置为计算一些坐标(xi目标(10)在一个时刻i处的位置,如下所示:-如果当前时刻和前一个时刻的旋转角度不同,则(xn,andn)=(xn -1,andn- 1); -如果两个图像帧相等,则(x {sub,n,n)=(xn-1,n -1); -在另一种情况下:-如果半径相等并且有多个标记,则使用两个图像帧通过三角测量来计算(xn和n); -如果半径不同并且有多个标记,则使用单个图像帧通过三角测量来计算(xn和n); -如果半径不同并且有单个标记,则(xn和n)通过立体几何计算; -如果半径相同并且有单个标记,则使用当前时间和上一个标记的图像坐标来计算(xn和n)。 (通过Google翻译进行机器翻译,没有法律约束力)

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