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Method for identifying the anti-HVE IgG marker in the blood serum

机译:血清中抗HVE IgG标志物的鉴定方法

摘要

The invention relates to medicine, namely to a method for identifying the anti-HVE IgG marker in the blood serum and can be used for the diagnosis of viral hepatitis E in persons in the food industry.Summary of the invention consists in examining the blood serum in the enzyme immunoassay using a microplate with adsorbed AgHVE and determining the optical density values of the samples by a photometric method at a wavelength of 450…620 nm, then determining the average optical density value of the samples with negative control according to the formula: average of the optical densities of the samples with negative control + 0.350, then determining the ratio of the average optical density value of the patient's serum and the average optical density value of the samples with negative control and if the ratio is up to 0.9, it is considered that the result is negative, if more than 1.1 it is positive, and samples with a result of 0.9…1.1 are treated with a 20% slurry of kaolin of the formula Al2O3·2SiO2·2H2O, then the said enzyme immunoassay is repeated, followed by the determination of the ratio of the average optical density value of the patient's serum and the average optical densities value with negative control + 0.350, if the ratio is up to 0.9, it is considered that the result is negative, and if more than 1.1 the result is positive.
机译:本发明涉及药物,即一种在血清中鉴定抗HVE IgG标志物的方法,可用于食品工业人员中戊型肝炎病毒的诊断。在酶免疫分析中使用吸附有AgHVE的微孔板,并通过光度法在450…620 nm波长处确定样品的光密度值,然后根据下式确定带有阴性对照的样品的平均光密度值:取阴性对照样本的平均光密度值的平均值+ 0.350,然后确定患者血清的平均光学密度值与阴性对照样本的平均光密度值的比值,如果该比值最高为0.9认为结果为负,如果大于1.1,则为正,并用20%的式Al高岭土浆料处理结果为0.9…1.1的样品2O3·2SiO2·2H2O,然后重复进行上述酶免疫测定,然后测定患者血清的平均光密度值与阴性对照的平均光密度值之比+0.350(如果该比值最高为0.9) ,则认为结果为负,如果大于1.1,则结果为正。

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