A titanium-based intermetallic alloy includes, in atomic percent, 16% to 26% Al, 18% to 28% Nb, 0% to 3% of a metal M selected from Mo, W, Hf, and V, 0.1% to 2% of Si, 0% to 2% of Ta, 1% to 4% of Zr, with the condition Fe+Ni≤400 ppm, the balance being Ti, the alloy also presenting an Al/Nb ratio in atomic percent lying in the range 1.05 to 1.15.
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机译：钛基金属间合金以原子百分比包括16％至26％的Al，18％至28％的Nb，0％至3％的选自Mo，W，Hf和V的金属M，0.1％至2 Fe +Ni≤400ppm，其余条件为Ti，Si含量为0％，Ta含量为0％至2％，Zr含量为1％至4％，合金中Al / Nb的原子百分比也位于范围是1.05至1.15。
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