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A Proof of the Orbit Conjecture for Flipping Edge-Labelled Triangulations

机译:用于翻转边缘标记三角剖分的轨道猜想的证明

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摘要

Given a triangulation of a point set in the plane, a flip deletes an edge e whose removal leaves a convex quadrilateral, and replaces e by the opposite diagonal of the quadrilateral. It is well known that any triangulation of a point set can be reconfigured to any other triangulation by some sequence of flips. We explore this question in the setting where each edge of a triangulation has a label, and a flip transfers the label of the removed edge to the new edge. It is not true that every labelled triangulation of a point set can be reconfigured to every other labelled triangulation via a sequence of flips, but we characterize when this is possible. There is an obvious necessary condition: for each label l, if edge e has label l in the first triangulation and edge f has label l in the second triangulation, then there must be some sequence of flips that moves label l from e to f, ignoring all other labels. Bose, Lubiw, Pathak and Verdonschot formulated the Orbit Conjecture, which states that this necessary condition is also sufficient, i.e. that all labels can be simultaneously mapped to their destination if and only if each label individually can be mapped to its destination. We prove this conjecture. Furthermore, we give a polynomial-time algorithm to find a sequence of flips to reconfigure one labelled triangulation to another, if such a sequence exists, and we prove an upper bound of O(n^7) on the length of the flip sequence. Our proof uses the topological result that the sets of pairwise non-crossing edges on a planar point set form a simplicial complex that is homeomorphic to a high-dimensional ball (this follows from a result of Orden and Santos; we give a different proof based on a shelling argument). The dual cell complex of this simplicial ball, called the flip complex, has the usual flip graph as its 1-skeleton. We use properties of the 2-skeleton of the flip complex to prove the Orbit Conjecture.
机译:给定在平面上设置的点的三角剖分,翻转将删除边缘e,该边缘e的去除留下凸四边形,并用四边形的对角线替换e。众所周知,可以通过一系列翻转将点集的任何三角剖分重新配置为任何其他三角剖分。我们在三角剖分的每个边都有标签,然后翻转将移除边的标签转移到新边的设置中探索这个问题。可以通过一系列翻转将点集的每个带标记的三角剖分重新配置为每个其他带标记的三角剖分,但这是不正确的,但是我们描述了何时可以做到这一点。存在一个明显的必要条件:对于每个标签l,如果边e在第一个三角剖分中具有标签l,而边f在第二个三角剖分中具有标签l,则必须存在一系列将标签l从e移至f的翻转序列,忽略所有其他标签。 Bose,Lubiw,Pathak和Verdonschot制定了Orbit Conjecture,其中指出此必要条件也已足够,即当且仅当每个标签可以分别映射到其目的地时,所有标签才能同时映射到其目的地。我们证明了这个猜想。此外,我们给出了多项式时间算法来查找翻转序列,以将一个标记的三角剖分重新配置为另一个,如果存在这样的序列,我们证明了翻转序列的长度为O(n ^ 7)的上限。我们的证明使用的拓扑结果是,平面点集上成对的非交叉边的集合形成了一个对高维球同胚的简单复形(这来自Orden和Santos的结果;我们基于在脱壳参数上)。这个简单球的双单元复合物称为翻转复合物,具有通常的翻转图作为其1骨架。我们使用翻转复合物的2骨架的属性来证明轨道猜想。

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