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Four Random Permutations Conjugated by an Adversary Generate S-n with High Probability

机译:对手共轭的四个随机置换生成具有高概率的S-n

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摘要

We prove a conjecture dating back to a 1978 paper of D.R. Musser [11], namely that four random permutations in the symmetric group S-n generate a transitive subgroup with probability p(n) > epsilon for some epsilon > 0 independent of n, even when an adversary is allowed to conjugate each of the four by a possibly different element of S-n. In otherwords, the cycle types already guarantee generation of a transitive subgroup; by a well known argument, this implies generation of A(n) or S-n except for probability 1+ o(1) as n -> infinity. The analysis is closely related to the following random set model. A random set M subset of Z(+) is generated by including each n >= 1 independently with probability 1. The sumset sumset(M) is formed. Then at most four independent copies of sumset(M) are needed before their mutual intersection is no longer infinite. (C) 2015 Wiley Periodicals, Inc.
机译:我们证明了一个可追溯到1978年D.R. Musser [11],即对称组Sn中的四个随机置换生成一个传递子组,对于某些epsilon> 0,概率p(n)> epsilon,与n无关,即使允许对手用a缀合这四个变量中的每一个锡的可能不同的元素。换句话说,循环类型已经可以保证传递子组的生成。根据一个众所周知的论点,这意味着生成A(n)或S-n,除了概率1+ o(1)为n->无穷大。该分析与以下随机集模型密切相关。 Z(+)的随机集合M子集通过以概率1 / n独立地包含每个n> = 1来生成。形成和集sumset(M)。然后,最多需要四个sumset(M)独立副本,然后它们的相互交集不再是无限的。 (C)2015威利期刊公司

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