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On the factorization of LCM matrices on gcd-closed sets

机译:关于gcd闭集上的LCM矩阵的因式分解

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Let S = {x(1),..., x(n)} be a set of n distinct positive integers. The matrix having the greatest common divisor (GCD) (x(i), x(j)) of x(i) and x(j) as its i, j-entry is called the greatest common divisor matrix, denoted by (S)n. The matrix having the least common multiple (LCM) [x(i), x(j)] of xi and xj as its i, j-entry is called the least common multiple matrix, denoted by [S], The set is said to be gcd-closed if (x(i), x(j)) is an element of S for all 1 less than or equal to i, j less than or equal to n. In this paper we show that if n less than or equal to 3, then for any gcd-closed set S = {x(1),...,x(n)}, the GCD matrix on S divides the LCM matrix on S in the ring Mn(Z) of n x n matrices over the integers. For n greater than or equal to 4, there exists a gcd-closed set S = {x(1),...,x(n)} such that the GCD matrix on S does not divide the LCM matrix on S in the ring Mn (Z). This solves a conjecture raised by the author in 1998. (C) 2002 Elsevier Science Inc. All rights reserved. [References: 14]
机译:令S = {x(1),...,x(n)}是一组n个不同的正整数。将x(i)和x(j)的最大公约数(GCD)(x(i),x(j))作为其i,j项的矩阵称为最大公约数矩阵,用(S )n。将xi和xj的最小公倍数(LCM)[x(i),x(j)]作为其i,j项的矩阵称为最小公倍数矩阵,用[S]表示。如果(x(i),x(j))是S的元素,且所有1小于或等于i,j小于或等于n,则将被关闭。在本文中,我们表明,如果n小于或等于3,则对于任何gcd闭集S = {x(1),...,x(n)},S上的GCD矩阵将LCM矩阵除以在整数上的nxn个矩阵的环Mn(Z)中的S。对于大于或等于4的n,存在一个gcd闭集S = {x(1),...,x(n)},使得S上的GCD矩阵不将S上的LCM矩阵除环Mn(Z)。这解决了作者在1998年提出的一个猜想。(C)2002 Elsevier Science Inc.保留所有权利。 [参考:14]

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