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On the computation of median linear orders, of median complete preorders and of median weak orders

机译:关于中位数线性订单,中位数完整预订单和中位数弱订单的计算

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Given a finite set X and a collection Π, called a profile, of binary relations defined on X (which can be linear orders, complete preorders, any relations, and so on), a relation R is said to be median if it minimizes the total number of disagreements with respect to Π. In the context of voting theory, X can be considered as a set of candidates and the relations of Π as the preferences of voters, while a median relation can be adopted as the collective preference with respect to the voters' opinions. If the relations of Π are tournaments (which includes linear orders), then there always exists a median complete preorder (i.e. a median complete and transitive relation) which is in fact a linear order. Moreover, if there is no tie when aggregating the tournaments of Π, then all the median complete preorders are linear orders. We show the same when the median is assumed to be a weak order (a weak order being the asymmetric part of a complete preorder). We then deduce from this that the computation of a median complete preorder or of a median weak order of a profile Π of m linear orders is NP-hard for any even m greater than or equal to 4 or for odd m large enough with respect to {pipe}X{pipe} (about {pipe}X{pipe} ~2). We then sharpen these complexity results when coping with other kinds of profiles Π for odd values of m. In particular, when the relations of Π and the median relation are complete preorders, we obtain the same results for the NP-hardness of Kemeny's problem.
机译:给定一个有限集X和一个在X上定义的二进制关系的集合,(称为轮廓)(可以是线性顺序,完整的预顺序,任何关系等),如果关系R最小化关系R,则称其为中值。关于Π的分歧总数。在投票理论的背景下,X可被视为一组候选人,而Π的关系可被视为选民的偏好,而中值关系可被视为相对于选民的意见的集体偏好。如果the的关系是锦标赛(包括线性顺序),则总存在中位数完整的预排序(即中位数完整和传递关系),而实际上是线性顺序。此外,如果在汇总Π的锦标赛时没有平局,则所有中位数完整的预订单均为线性订单。当中位数被假定为弱阶时(弱阶是完整预序的不对称部分),我们将显示相同的结果。然后我们据此推论,对于任何大于等于4的偶数m或相对于m足够大的奇数m而言,m个线性阶次的Π的中位数完整预序或中位数弱阶的计算都是NP-难的。 {pipe} X {pipe}(约{pipe} X {pipe}〜2)。然后,当针对m的奇数值处理其他类型的Π时,我们会提高这些复杂性结果。尤其是,当relations与中位数的关系为完整的预序时,我们对Kemeny问题的NP硬度获得相同的结果。

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