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About the sharpness of the stability estimates in the Kreiss matrix theorem

机译:关于Kreiss矩阵定理中稳定性估计的锐度

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One of the conditions in the Kreiss matrix theorem involves the resolvent of the matrices A under consideration. This so-called resolvent condition is known to imply, for all n greater than or equal to 1, the upper bounds parallel toA(n)parallel to less than or equal to eK(N + 1) and parallel toA(n)parallel to less than or equal to eK(n + 1). Here parallel to . parallel to is the spectral norm, K is the constant occurring in the resolvent condition, and the order of A is equal to N + 1 greater than or equal to 1. It is a long-standing problem whether these upper bounds can be sharpened, for all fixed K > 1, to bounds in which the right-hand members grow much slower than linearly with N + 1 and with n + 1, respectively. In this paper it is shown that such a sharpening is impossible. The following result is proved: for each c > 0, there are fixed values C > 0, K > 1 and a sequence of (N + 1) x (N + 1) matrices AN, satisfying the resolvent condition, such that parallel to(A(N))(n)parallel to greater than or equal to C(N + 1)(1-epsilon) = C(n + 1)(1-epsilon) for N = n = 1, 2, 3,.... The result proved in this paper is also relevant to matrices A whose epsilon-pseudospectra lie at a distance not exceeding Kepsilon from the unit disk for all epsilon > 0. [References: 22]
机译:Kreiss矩阵定理中的条件之一涉及所考虑的矩阵A的分解。已知这种所谓的分解条件意味着,对于所有大于或等于1的n,平行于A(n)的上限平行于小于或等于eK(N +1)且平行于A(n)的上限平行于小于或等于eK(n + 1)。这里平行于。与光谱范数平行,K是在分解条件下发生的常数,并且A的阶数等于或大于1等于N +1。是否可以提高这些上限是一个长期的问题,对于所有固定K> 1,到右手边分别比N + 1和n + 1线性增长慢得多的边界。在本文中显示了这种锐化是不可能的。证明以下结果:对于每个c> 0,存在固定值C> 0,K> 1和(N + 1)x(N + 1)个矩阵AN的序列,满足分解条件,使得与(A(N))(n)平行于C等于或等于C(N +1)(1-ε)= C(n +1)(1-ε),其中N = n = 1,2,3, ....本文证明的结果也与矩阵A有关,对于所有epsilon> 0,矩阵A的epsilon-pseudospectra距单位圆盘的距离均不超过Kepsilon。[参考:22]

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