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An analytical treatment of the clock paradox in the framework of the special and general theories of relativity

机译:在狭义相对论和广义相对论的框架下对时钟悖论的分析性处理

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In this paper we treat the so called clock paradox in an analytical way by assuming that a constant and uniform force F of finite magnitude acts continuously on the moving clock along the direction of its motion assumed to be rectilinear (in space). No inertial motion steps are considered. The rest clock is denoted as (1), the to-and-fro moving clock is (2), the inertial frame in which (1) is at rest in its origin and (2) is seen moving is I and, finally, the accelerated frame in which (2) is at rest in its origin and (1) moves forward and backward is A. We deal with the following questions: (1) What is the effect of the finite force acting on (2) on the proper time interval Deltatau((2)) measured by the two clocks when they reunite? Does a differential aging between the two clocks occur, as it happens when inertial motion and infinite values of the accelerating force is considered? The special theory of relativity is used in order to describe the hyperbolic (in spacetime) motion of (2) in the frame I. (II) Is this effect an absolute one, i.e., does the accelerated observer A comoving with (2) obtain the same results as-that obtained by the observer in 1, both qualitatively and quantitatively, as it is expected? We use the general theory of relativity in order to answer this question. It turns out that Deltatau(I) = Deltatau(A) for both the clocks, Deltatau((2)) does depend on g = F/m, and Deltatau((2)) /Deltatau((1)) = (root1-beta(2)atanhbeta)/beta < 1. In it β = V/c and V is the velocity acquired by (2) when the force is inverted.
机译:在本文中,我们通过分析方法来处理所谓的时钟悖论,方法是假设一个恒定大小的恒定且均匀的力F沿被假定为直线(在空间中)运动的方向连续作用于运动的时钟。不考虑惯性运动步长。其余时钟表示为(1),来回移动时钟为(2),其中(1)静止的惯性系为(1)静止,而(2)可见的惯性系为I,最后, (2)在其原点处于静止状态并且(1)向前和向后移动的加速框架为A。我们处理以下问题:(1)作用于(2)的有限力对轴的作用是什么?两个时钟重新组合时,由两个时钟测量的适当时间间隔Deltatau((2))?当考虑惯性运动和无限大的加速力时,是否会出现两个时钟之间的差分老化?为了描述(2)在帧I中的双曲(时空)运动,使用了相对论的特殊理论。(II)这种效应是绝对的吗,即与(2)共同运动的加速观测者A是否获得了与观察者在1中获得的定性和定量结果是否相同?我们使用相对论的一般理论来回答这个问题。事实证明两个时钟的Deltatau(I)= Deltatau(A),Deltatau((2))确实取决于g = F / m,并且Deltatau((2))/ Deltatau((1))=(root1 -β(2)atanhβ)/β<1。其中β= V / c,V是力反向时由(2)求出的速度。

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