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首页> 外文期刊>Forensic science international. Genetics >Fundamental problem of forensic mathematics--the evidential value of a rare haplotype.
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Fundamental problem of forensic mathematics--the evidential value of a rare haplotype.

机译:法医学的基本问题-一种罕见的单倍型的证据价值。

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Y-chromosomal and mitochondrial haplotyping offer special advantages for criminal (and other) identification. For different reasons, each of them is sometimes detectable in a crime stain for which autosomal typing fails. But they also present special problems, including a fundamental mathematical one: When a rare haplotype is shared between suspect and crime scene, how strong is the evidence linking the two? Assume a reference population sample is available which contains n-1 haplotypes. The most interesting situation as well as the most common one is that the crime scene haplotype was never observed in the population sample. The traditional tools of product rule and sample frequency are not useful when there are no components to multiply and the sample frequency is zero. A useful statistic is the fraction kappa of the population sample that consists of singletons probability for a random innocent suspect to match a previously unobserved crime scene type is (1-kappa) - distinctly less than 1, likely ten times less. The robust validity of this model is confirmed by testing it against a range of population models. This paper hinges above all on one key insight: probability is not frequency. The common but erroneous "frequency" approach adopts population frequency as a surrogate for matching probability and attempts the intractable problem of guessing how many instances exist of the specific haplotype at a certain crime. Probability, by contrast, depends by definition only on the available data. Hence if different haplotypes but with the same data occur in two different crimes, although the frequencies are different (and are hopelessly elusive), the matching probabilities are the same, and are not hard to find.
机译:Y染色体和线粒体单体型为犯罪(和其他)鉴定提供了特殊优势。由于不同的原因,它们中的每一个有时都可以在常染色体分型失败的犯罪斑点中检测到。但是它们也存在一些特殊的问题,包括一个基本的数学问题:当犯罪嫌疑人和犯罪现场之间共享一种罕见的单倍型时,将两者联系起来的证据有多强?假设有一个包含n-1个单倍型的参考种群样本。最有趣和最常见的情况是,在人口样本中从未观察到犯罪现场单倍型。当没有要乘的分量且采样频率为零时,传统的乘积法则和采样频率工具将无用。有用的统计数据是人口样本的kappa分数,该kappa分数由随机无辜犯罪嫌疑人匹配之前未观察到的犯罪现场类型的单例概率为(1-kappa)/ n-明显小于1 / n,可能小十倍。通过针对一系列总体模型进行测试,可以确认该模型的鲁棒有效性。本文首先取决于一个关键的见解:概率不是频率。常见但错误的“频率”方法采用人口频率作为匹配概率的替代指标,并尝试解决在某种犯罪情况下猜测特定单倍型存在多少实例的棘手问题。相反,根据定义,概率仅取决于可用数据。因此,如果在两种不同的犯罪中发生具有相同数据的不同单倍型,尽管频率不同(并且难以捉摸),但匹配的概率是相同的,并且不难发现。

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