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首页> 外文期刊>Bernoulli: official journal of the Bernoulli Society for Mathematical Statistics and Probability >Slow, fast and arbitrary growth conditions for renewal-reward processes when both the renewals and the rewards are heavy-tailed
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Slow, fast and arbitrary growth conditions for renewal-reward processes when both the renewals and the rewards are heavy-tailed

机译:当续签和奖励都被拖尾时,续签奖励过程的缓慢,快速和任意增长条件

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摘要

Consider M independent and identically distributed renewal-reward processes with heavy-tailed renewals and rewards that have either finite variance or heavy tails. Let W~*(Ty, M), y ∈ [0, 1], denote the total reward process computed as the sum of all rewards in M renewal-reward processes over the time interval [0, T]. If T → ∞ and then M → ∞, Taqqu and Levy have shown that the properly normalized total reward process W~(T, M) converges to the stable Levy motion, but, if M → ∞followed by T → ∞, the limit depends on whether the tails of the rewards are lighter or heavier than those of renewals. If they are lighter, then the limit is a self-similar process with stationary and dependent increments. If the rewards have finite variance, this self-similar process is fractional Brownian motion, and if they are heavy-tailed rewards, it is a stable non-Gaussian process with infinite variance. We consider asymmetric rewards and investigate what happens when M and T go to infinity jointly, that is, when M is a function of T and M = M(T) → ∞ as T → ∞. We provide conditions on the growth of M for the total reward process W~*(T, M(T)) to converge to any of the limits stated above, as T → ∞. We also show that when the tails of the rewards are heavier than the tails of the renewals, the limit is stable Levy motion as M = M(T) → ∞, irrespective of the function M(T).
机译:考虑M个独立的且分布均匀的续签-奖励流程,该续签-奖励流程具有有限的方差或繁重的尾部,并且具有大量的续签和奖励。令W〜*(Ty,M),y∈[0,1],表示总的奖励过程,计算为在时间间隔[0,T]中,M个更新-奖励过程中所有奖励的总和。如果T→∞,然后是M→∞,则Taqqu和Levy已证明适当归一化的总奖励过程W〜(T,M)收敛到稳定的Levy运动,但是,如果M→∞随后是T→∞,则极限取决于奖励的尾巴比续约的尾巴更轻或更重。如果它们更轻,则限制是一个自相似的过程,具有固定的和相关的增量。如果奖励具有有限方差,则此自相似过程是分数布朗运动;如果奖励是重尾奖励,则它是具有无限方差的稳定非高斯过程。我们考虑非对称奖励,并研究当M和T共同达到无穷大时(即M是T的函数并且M = M(T)→∞为T→∞)时会发生什么。我们为总奖励过程W〜*(T,M(T))的M增长提供条件,以收敛到上述任何一个限制,即T→∞。我们还表明,当奖励的尾部比续约的尾部重时,无论函数M(T)如何,该限制都是稳定的Levy运动,如M = M(T)→∞。

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