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首页> 外文期刊>Bulletin of the Seismological Society of America >A short note on the selection of the fault plane, the seismic moment tensor, the strain and rotational tensors, and the gradient of displacement
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A short note on the selection of the fault plane, the seismic moment tensor, the strain and rotational tensors, and the gradient of displacement

机译:关于断层平面,地震矩张量,应变和旋转张量以及位移梯度的选择的简短说明

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摘要

The gradient of displacement of the ground produced by a dislocation (at a point or finite) is the sum of a deformation part and a rotational part. The deformation part, which is symmetric, is usually deduced from seismology via the seismic moment tensor, which is also symmetric. The rotational part, which is antisymmetric, is usually deduced from paleomagnetism. It can not be deduced from the symmetric seismic moment tensor M-ij. Nevertheless, if the selection of the fault plane is possible, the rotational tensor can be calculated from the asymmetric tensor C-ij = v(i)n(j) where n(i) and v(i) are the components of the normal vector to the fault and the slip vector on this fault, respectively. When the selection of the fault plane is possible, the seismic moment tensor M-ij is not so appropriate to describe the source because of its intrinsic symmetric character. The tensor C-ij may be better, and the gradient of displacement itself could be used instead of the strain tensor. [References: 8]
机译:由位错(在一个点或有限的位置)产生的地面位移的梯度是变形部分和旋转部分的总和。通常是通过对称的地震矩张量从地震学推导出对称的变形部分。旋转部分是反对称的,通常是从古电磁学推论得出的。它不能从对称地震矩张量M-ij推导出。但是,如果可以选择断层平面,则可以从非对称张量C-ij = v(i)n(j)计算旋转张量,其中n(i)和v(i)是法线的分量断层的矢量和该断层的滑动矢量。当可能选择断层面时,由于其固有的对称性,地震矩张量M-ij不太适合描述震源。张量C-ij可能更好,并且可以使用位移梯度本身代替应变张量。 [参考:8]

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