首页> 外文期刊>Inventiones Mathematicae >Finiteness of integral values for the ratio of two linear recurrences
【24h】

Finiteness of integral values for the ratio of two linear recurrences

机译:两个线性递归之比的积分值的有限性

获取原文
获取原文并翻译 | 示例
获取外文期刊封面目录资料

摘要

Let {F(n)_(n∈N)}, {G(n)_(n∈N)}, be linear recurrent sequences. In this paper we are concerned with the well-known diophantine problem of the finiteness of the set N of natural numbers n such that F(n)/G(n) is an integer. In this direction we have for instance a deep theorem of van der Poorten; solving a conjecture of Pisot, he established that if N coincides with N, then {F(n)/G(n)}_(n∈N) is itself a linear recurrence sequence. Here we shall prove that if N is an infinite set, then there exists a nonzero polynomial P such that P(n)F(n)/G(n) coincides with a linear recurrence for all n in a suitable arithmetic progression. Examples like F(n) = 2~n - 2, G(n) = n + 2~n + (-2)~n, show that our conclusion is in a sense best-possible. In the proofs we introduce a new method to cope with a notorious crucial difficulty related to the existence of a so-called dominant root. In an appendix we shall also prove a zero-density result for N in the cases when the polynomial P cannot be taken a constant.
机译:令{F(n)_(n∈N)},{G(n)_(n∈N)}为线性递归序列。在本文中,我们关注自然数为n的集合N的有限性使得F(n)/ G(n)为整数的有限度的众所周知的双色子问题。例如,在这个方向上,我们有范德普顿的一个深定理;解决Pisot的一个猜想时,他确定如果N与N重合,则{F(n)/ G(n)} _(n∈N)本身就是线性递归序列。在这里,我们将证明,如果N是一个无限集,那么将存在一个非零多项式P,使得P(n)F(n)/ G(n)与所有n的线性递归在适当的算术级数中重合。例如F(n)= 2〜n-2,G(n)= n + 2〜n +(-2)〜n,表明我们的结论在某种意义上是最好的。在证明中,我们介绍了一种新方法来应对与存在所谓显性根有关的众所周知的关键难题。在附录中,当多项式P不能取常数时,我们还将证明N的零密度结果。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号