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首页> 外文期刊>Inorganica Chimica Acta >Rhodium aryloxide complexes containing terdentate nitrogen ligands, C-O bond formation, hydrogen bonding with phenol and oxidative addition reactions. Molecular structure of an Rh(III)-acetyl complex
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Rhodium aryloxide complexes containing terdentate nitrogen ligands, C-O bond formation, hydrogen bonding with phenol and oxidative addition reactions. Molecular structure of an Rh(III)-acetyl complex

机译:芳氧基铑配合物,含有叔氮配体,C-O键形成,与苯酚的氢键结合和氧化加成反应。 Rh(III)-乙酰基配合物的分子结构

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摘要

The new rhodium(I) phenoxide complexes [Rh(OPh)(2,6-(CH=NR2)(2)C5H3N)] (R-2 = i-Pr (3), t-Ba (4)) containing strongly electron-donating N-N'-N ligands, have been prepared by a metathesis reaction of [RhCl(2,6-(CH=NR2)(2)C5H3N)] (R-2= i-Pr (1), t-Bu (2)) with NaOPh. These rhodium(I) phenoxide complexes 3 and 4, which are very sensitive to O-2 but stable towards H2O, give with phenol the adducts [Rh(OPh) (2,6-(CH=NR2)(2)C5H3N)]. HOPh (R-2 = i-Pr (5), t-Bu (6)), which contain strong O-H ... O hydrogen bonds. The hydrogen bonded phenol could not be extracted with diethyl ether, while no exchange of the hydrogen bonded phenol and the phenoxide ligand in 4 is observed on the NMR time scale, However, a small excess of phenol results in exchange of the hydrogen bonded phenol, the coordinated phenoxide ligand and free phenol on the NMR time scale. Reaction of 3 and 4 with p-nitrophenol afforded [Rh(OC6H4-(NO2-4)(2,6-(CH=NR2)(2)C5H3N)]. HOPh (R-2 = i-Pr (7), t-Bu (8)) in which the formed phenol is hydrogen bonded to the Rh(I)-OC6H4-(NO2-4) moiety, The O-H ... O bond is less strong than in 5 and 6, as the hydrogen bonded phenol could be removed by diethyl ether. Treatment of 3 with acetyl chloride and benzoyl chloride in benzene at room temperature gave phenylacetate and [RhCl2(C(O)CH3)(2,6(C(H)=N-i-Pr)(2)C5H3N)] (15), and phenylbenzoate and [RhCl2(C(O)Ph)(2,6-(C(H)=N-i-Pr)(2)C5H3N)] (19), respectively, Complex 15 and the analogous complex [RhCl2(C(O)CH3)(2,6-(C(H)=N-t-Bu)(2)C5H3N)] (16) could also be prepared directly from acetyl chloride and 1 or 2, respectively. The single crystal X-ray determination of complex 16, monoclinic, space group P2(1)/c, a=10.0477(5), b = 11.7268(6), c= 19.2336(9)Angstrom, beta = 92.041(4)degrees, Z= 4, R-1 = 0.0281, shows that the acetyl group occupies an axial position, while the N-N'-N ligand is positioned equatorially. In solution this geometry remains unchanged as was shown by variable temperature H-1 NMR measurements. When the oxidative addition of acetyl chloride to 3 was carried out al -78 degrees C in toluene the intermediate complex [RhCl(OPh)(C(O)Me)(2,6-(C(H)=N-i-Pr)(2)C5H3N)] (11) could be isolated, which at room temperature reductively eliminates phenylacetate with formation of 1. Oxidative addition of acetyl chloride to 4 at room temperature gives [RhCl(OPh)(C(O)Me)(2,6-(C(H)=Nt-Bu)(2)C5H3N)] (12) which yields phenylacetate and 2 at 70 degrees C in benzene by reductive elimination. Treatment of 3 with two equivalents of benzyl chloride afforded a mixture of [RhCl(OPh)(CH2Ph)(2,6-(C(H)=N-i-Pr)(2)C5H3N)] (13) and [RhCl2(CH2Ph)(2,6-(C(H)=N-i-Pr)(2)C5H3N)] (17) and some non-characterizable organic products, while 4 only yielded [RhCl2(OPh)(CH2Ph)(2,6-(C(H)=N-t-Bu)(2)C5H3N)](14). (C) 1998 Elsevier Science S.A. [References: 57]
机译:新的苯酚铑(I)配合物[Rh(OPh)(2,6-(CH = NR2)(2)C5H3N)](R-2 = i-Pr(3),t-Ba(4))含有强通过[RhCl(2,6-(CH = NR2)(2)C5H3N)]的复分解反应制备给电子电子的N-N'-N配体(R-2 = i-Pr(1),t -Bu(2))与NaOPh。这些对O-2非常敏感但对H2O稳定的苯酚铑(I)配合物3和4与苯酚产生加合物[Rh(OPh)(2,6-(CH = NR2)(2)C5H3N)] 。 HOPh(R-2 = i-Pr(5),t-Bu(6)),其中包含强O-H ... O氢键。氢键酚不能用二乙醚萃取,而在NMR时间尺度上未观察到氢键酚与酚盐配体在4中的交换,但是,少量过量的苯酚会导致氢键酚的交换,在NMR时标上的配位酚盐配体和游离酚3和4与对硝基苯酚反应得到[Rh(OC6H4-(NO2-4)(2,6-(CH = NR2)(2)C5H3N))。HOPh(R-2 = i-Pr(7), t-Bu(8)),其中形成的酚氢键合到Rh(I)-OC6H4-(NO2-4)部分,OH ... O键不如5和6中的氢键强可以用乙醚除去键合的苯酚,在室温下用乙酰氯和苯甲酰氯在苯中处理3,得到苯乙酸酯和[RhCl2(C(O)CH3)(2,6(C(H)= Ni-Pr)( 2)C5H3N)](15),以及苯甲酸苯酯和[RhCl2(C(O)Ph)(2,6-(C(H)= Ni-Pr)(2)C5H3N)]](19),络合物15并且类似的络合物[RhCl2(C(O)CH3)(2,6-(C(H)= Nt-Bu)(2)C5H3N))(16)也可以直接由乙酰氯和1或2制备,单晶X射线测定复合物16,单斜晶,空间群P2(1)/c、a=10.0477(5),b = 11.7268(6),c = 19.2336(9)埃,β= 92.041( 4)度,Z = 4,R-1 = 0.0281,表明乙酰基占据轴向位置,而N-N′-N配体为p。赤道定位。在溶液中,此几何形状保持不变,如通过可变温度H-1 NMR测量所显示的。当在-78°C下于甲苯中将乙酰氯氧化成3时,中间体配合物[RhCl(OPh)(C(O)Me)(2,6-(C(H)= Ni-Pr)( 2)C5H3N)](11),可在室温下还原除去乙酸苯酯,形成1。在室温下将乙酰氯氧化加成4得[RhCl(OPh)(C(O)Me)(2, 6-(C(H)= Nt-Bu)(2)C5H3N)](12)通过还原消除在苯中在70℃下产生乙酸苯酯和2。用两当量的苄基氯处理3,得到[RhCl(OPh)(CH2Ph)(2,6-(C(H)= Ni-Pr)(2)C5H3N)](13)和[RhCl2(CH2Ph )(2,6-(C(H)= Ni-Pr)(2)C5H3N)](17)和一些不可表征的有机产物,而4仅产生[RhCl2(OPh)(CH2Ph)(2,6- (C(H)= Nt-Bu)(2)C5H3N)](14)。 (C)1998 Elsevier Science S.A. [参考:57]

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