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Monochromatic k-edge-connection colorings of graphs

机译:图形的单色k边缘连接着色

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A path in an edge-colored graph G is called monochromatic if any two edges on the path have the same color. For k >= 2, an edge-colored graph G is said to be monochromatic k-edge-connected if every two distinct vertices of G are connected by at least k edge-disjoint monochromatic paths, and G is said to be uniformly monochromatic k-edge-connected if every two distinct vertices are connected by at least k edge-disjoint monochromatic paths such that all edges of these k paths are colored with a same color. We use mc(k)(G) and umc(k)(G) to denote the maximum number of colors that ensures G to be monochromatic k-edge-connected and, respectively, G to be uniformly monochromatic k-edge-connected. In this paper, we first conjecture that for any k-edge-connected graph G, mc(k)(G) = e(G) - e(H)+[k/2], where H is a minimum k-edge-connected spanning subgraph of G. We verify the conjecture for k = 2. We also prove the conjecture for G = Kk+1 and G = K-k,K-n with n >= k >= 3. When G is a minimal k-edge-connected graph, we give an upper bound of mc(k)(G), i.e., mc(k)(G) <= k-1. For the uniformly monochromatic k-edge-connectivity, we prove that for all k, umc(k)(G) = e(G) - e(H) + 1, where H is a minimum k-edge-connected spanning subgraph of G. (C) 2019 Elsevier B.V. All rights reserved.
机译:如果路径上的任何两个边缘具有相同的颜色,则边缘色图G中的路径称为单色。对于k> = 2,如果通过至少k个边缘不相交的单色路径连接,则据说边缘彩色的曲线图G被置于单色k边缘连接,如果通过至少k个边缘不相交的单色路径连接,则据说G均匀单色k - 如果每个两个不同的顶点通过至少k个边缘不相交的单色路径连接,则连接到的,使得这些K路径的所有边缘都是具有相同颜色的。我们使用MC(k)(g)和UMC(k)(g)表示确保g为单色k侧连接的最大颜色数,并且分别为g均匀地单色k边缘连接。在本文中,我们首先猜测任何K边缘连接的图G,MC(k)(g)= e(g) - e(h)+ [k / 2],其中h是最小k边缘 - 连接G的跨越子图。我们验证了K = 2的猜想。我们还证明了G = KK + 1和G = KK的猜想,N> = K> = 3.当G是最小的K-Edge时连接图,我们给出了MC(k)(g)的上限,即mc(k)(g)<= k-1。对于均匀的单色k边缘连接,我们证明所有K,UMC(k)(g)= e(g) - e(h)+ 1,其中h是最小k边连接的跨越子图G.(c)2019 Elsevier BV保留所有权利。

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