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首页> 外文期刊>International journal of legal medicine >Inference of maternal uniparental disomy of the entire chromosome 2 from a paternity test
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Inference of maternal uniparental disomy of the entire chromosome 2 from a paternity test

机译:从亲子鉴定中推断整个染色体2的母体发起天使

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Atypical situations arise during the constant resolution of paternity cases, which constitute challenges requiring additional genetic systems and non-standard methods. We report a paternity case presenting three alleged father (AF)-child incompatibilities for the markers TPOX, D2S441, and the indel locus B02 (11/11 vs 8/8; 14/14 vs 10/10; 2/2 vs1/1, respectively). Considering the presence of mutations/null alleles, the residual paternity indexes (PI) obtained with 23 autosomal short tandem repeats (STRs) and 38 indels suggest that the AF is the father (PI=1.94e+011). Although the presence of few incompatibilities also could imply paternity of the AF brother, this hypothesis was less probable (PI=3.20e+9) (W=98.4 vs 1.6%, respectively). The inclusion of 23 Y-STR loci confirmed the paternity relationship in this case (global PI=6.08e+15). However, the two multistep STRs and one indel incompatibilities allow discarding the mutation possibility. On the other hand, the confirmation of the homozygous STR genotypes with two different human identification kits and the low probability to find three null alleles (3.10e-8) allow rejecting the null allele presence hypothesis. Conversely, the child's homozygous genotype for maternal alleles in four markers located in the p and q arms of the chromosome 2 (TPOX, D2S441, D2S1338, and B02) suggests that maternal uniparental isodisomy better explains the relationship despite the presence of three paternal incompatibilities. In brief, when multiple incompatibilities are observed in paternity testing, the chromosomal location of the excluding loci and the use of additional genetic systems can be crucial to get confident kinship conclusions.
机译:在持续解决父属病例的持续解决过程中出现的非典型情况,这构成了需要额外的遗传系统和非标准方法的挑战。我们报告了一个父亲案,呈现三个涉嫌父亲(AF) - 标记TPOX,D2S441和Indel Locus B02的父亲的不兼容性(11/11 Vs 8/8; 14/14 Vs 10/10; 2/2 Vs1 / 1 , 分别)。考虑到突变/零等位基因的存在,用23个常血糖短串联重复(strs)和38个indels获得的残留父病剂索引(pi)表明af是父(Pi = 1.94e + 011)。虽然存在很少的不相容性也可能意味着AF兄弟的父亲,但这种假设不太可能(PI = 3.20e + 9)(分别为98.4 vs 1.6%)。在这种情况下,包含23 y-str基因座(全局Pi = 6.08e + 15)确认了亲子关系。然而,两个多步骤和一个indel的不兼容允许丢弃突变可能性。另一方面,用两种不同的人鉴定试剂盒确认纯合子str基因型和寻找三个无效等位基因(3.10e-8)的低概率允许拒绝零等位基因存在假设。相反,儿童的纯合基因型为位于染色体2(TPOX,D2S441,D2S1338和B02)的P和Q臂中的四个标记中的母体等位基因表明,尽管存在三个父亲的不兼容性,但孕产妇144年和B02)表明孕产妇144年的异教表明这种关系。简而言之,当在亲子鉴定中观察到多种不相容性时,排除基因座的染色体位置和使用额外的遗传系统可能是至关重要的,以获得自信的亲属性结论。

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