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首页> 外文期刊>Computational & theoretical chemistry >The reactivity of coordinatively unsaturated iridium methylene complex Ir = CH2[N(SiMe2CH2PPh2)(2)]: A quantum chemistry study
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The reactivity of coordinatively unsaturated iridium methylene complex Ir = CH2[N(SiMe2CH2PPh2)(2)]: A quantum chemistry study

机译:协调不饱和铱亚甲基复合物IR = CH2的反应性[n(SIME2CH2PPH2)(2)]:量子化学研究

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The mechanisms for the reactions of the coordinatively unsaturated iridium methylene complex Ir = CH2[N(SiMe2CH2PPh2)](2) with a variety of small molecules including H-2, PMe3, CO, AI(2)Me(6), and CH3I have been investigated by the density functional theory (DFT) calculations. The calculation results showed that the reaction of methylene complex with Hy generates the trihydride amine IrH3[HN(SiMe2CH2PPh2)(2)] via a series of oxidative addition and reductive elimination steps. The reaction of methylene complex with PMe3 produces the square planar complex Ir(PMe3)[N(SiMe2CH2PPh2)(2)] and CH2 = PMe3, and the latter can further react with methylene complex to give ethene. The reaction of methylene complex with CO results in the formation of Ir(CO)[(CH2PPh2CH2SiMe2NSiMe2CH2PPh2)] by the formation of C-P bond. The reactions of methylene complex with Al2Me6 and methyl iodide were also examined, and the oxidative addition step can afford a metal-carbon bond that undergoes a C-C bond forming migratory insertion to ultimately lead to the formation of ethene. Present study can provide new insights into the reactivity of transition metal methylene complex.
机译:具有各种小分子,包括H-2,PME3,CO,AI(6)和CH3I的各种小分子的协调不饱和铱亚甲基复合物IR = CH2 [N(SIME2CH2PPH2PPH2)](2)的机制。已被密度泛函理论(DFT)计算研究。计算结果表明,通过一系列氧化加法和还原消除步骤,亚甲基络合物与Hy的反应产生三狼胺IRH3 [HN(SIME2CH2PPH2)(2)]。与PME3的亚甲基络合物的反应产生方形平面复合IR(PME3)[N(SIME2CH2PPH2)(2)]和CH2 = PME3,并且后者可以进一步与亚甲基络合物反应,得到乙烯。通过形成C-P键的亚甲基络合物与CO的反应导致IR(CO)[(CH2PPH2CH2Sime2NSIME2CH2PPH2]]的形成。还检查了亚​​甲基络合物与Al2ME6和甲基碘的反应,氧化加法步骤可提供金属 - 碳键,经历C-C键形成迁移插入,最终导致乙烯的形成。目前的研究可以为过渡金属亚甲基复合物的反应性提供新的见解。

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