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首页> 外文期刊>Dalton transactions: An international journal of inorganic chemistry >Discriminating role of bases in diketonate copper(i)-catalyzed C-O couplings: Phenol versus diarylether
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Discriminating role of bases in diketonate copper(i)-catalyzed C-O couplings: Phenol versus diarylether

机译:碱在二酮铜(i)催化的C-O偶联中的区别作用:苯酚与二芳基醚

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The mechanism of the formation of phenol from PhI and CsOH catalysed by copper(i) ligated to the 1,3-diketonate ket′- generated from 2,2,6,6-tetramethyl-3,5-heptanedione (TMHD) has been investigated by DFT calculations associated with experimental techniques: cyclic voltammetry, ~1H NMR, and ESI-MS. Weak halogen bonding between the negatively charged O atom of [(ket′)Cu~I-OH]- and PhI leads to an oxidative addition that gives (ket′)Cu~(III)(Ph)-OH. The latter undergoes a faster reductive elimination that delivers (ket′)Cu ~I(PhOH) from which PhOH is released. PhOPh is formed in the presence of an extra base Cs_2CO_3. The two catalytic cycles of formation of PhOH or PhOPh are branched at the level of (ket′)Cu ~I(PhOH) that can either afford PhOH in the presence of CsOH or be deprotonated by Cs_2CO_3 to generate [(ket′)Cu ~I-OPh]-. The oxidative addition of [(ket′)Cu ~I-OPh]- to PhI leads to (ket′)Cu~(III)(Ph)- OPh involved in a faster reductive elimination that delivers PhOPh and the CuI catalyst.
机译:铜(i)与由2,2,6,6-四甲基-3,5-庚二酮(TMHD)生成的1,3-二酮酮ket'-连接的铜(i)催化从PhI和CsOH形成苯酚的机理已被证实通过与实验技术相关的DFT计算进行了研究:循环伏安法,〜1H NMR和ESI-MS。 [(ket')Cu〜I-OH]-的带负电荷的O原子与PhI之间的弱卤素键导致氧化加成,从而产生(ket')Cu〜(III)(Ph)-OH。后者经历了更快的还原消除,释放出(ket')Cu〜I(PhOH),PhOH从中释放出来。 PhOPh在额外的碱基Cs_2CO_3的存在下形成。形成PhOH或PhOPh的两个催化循环在(ket')Cu〜I(PhOH)的水平上分支,在CsOH存在下可提供PhOH或被Cs_2CO_3脱质子化以生成[(ket'] Cu〜 I-OPh]-。 [(ket')Cu〜I-OPh]-氧化成PhI会导致(ket'] Cu〜(III)(Ph)-OPh参与更快的还原反应,从而释放出PhOPh和CuI催化剂。

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