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Implicant Size of a CNF Formula with Many Satisfying Assignments

机译:具有许多满意分配的CNF公式的隐式大小

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摘要

Consider any Boolean function F (X_1,...,X_N) that has more than 2~(-N)~δ 2·N satisfying assignments for some δ, 0 < δ < 1, and that can be expressed by a CNF formula with at most N~d clauses for some d > 0. Then how many variables do we need to fix in order to satisfy F? We show that one can always find some "short" partial assignment on which F evaluates to 1 by fixing at most αN variables for some constant α < 1; that is, F has an implicant of size ≤ αN. A lower bound for such α is also shown in terms of δ and d.
机译:考虑具有大于2〜(-N)〜δ2·N且满足某些δ,0 <δ<1且可以由CNF公式表示的布尔函数F(X_1,...,X_N)对于d> 0,最多包含N〜d个子句。那么为了满足F,我们需要修复多少个变量?我们表明,对于固定的常数<1,通过固定最多αN个变量,总是可以找到一些F取值为1的“短”部分赋值;也就是说,F的大小等于αN。这种α的下限也以δ和d表示。

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