首页> 外文期刊>Journal of Physical Organic Chemistry >Alkane oxidation by the system 'tert-butyl hydroperoxide-[Mn2L2O3][PF6](2) (L=1,4,7-trimethyl-1,4,7-triazacyclononane)-carboxylic acid'
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Alkane oxidation by the system 'tert-butyl hydroperoxide-[Mn2L2O3][PF6](2) (L=1,4,7-trimethyl-1,4,7-triazacyclononane)-carboxylic acid'

机译:氢氧烷叔丁基过氧化氢-[Mn2L2O3] [PF6](2)(L = 1,4,7-三甲基-1,4,7-三氮杂环壬烷)-羧酸的氧化

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The kinetics of cyclohexane (CyH) oxygenation with tert-butyl hydroperoxide (TBHP) in acetonitrile at 50 degrees C catalysed by a dinuclear manganese(IV) complex 1 containing 1,4,7-trimethyl-1,4,7-triazacyclononane and co-catalysed by oxalic acid have been studied. It has been shown that an active form of the catalyst (mixed-valent dimeric species '(MnMnIV)-Mn-III') is generated only in the interaction between complex 1 and TBHP and oxalic acid in the presence of water. The formation of this active form is assumed to be due to the hydrolysis of the Mn-O-Mn bonds in starting compound 1 and reduction of one Mn-IV to Mn-III. A species which induces the CyH oxidation is radical tert-BuO. generated by the decomposition of a monoperoxo derivative of the active form. The constants of the equilibrium formation and the decomposition of the intermediate adduct between TBHP and 1 have been measured: K = 7.4 mol(-1) dm(3) and k = 8.4 x 10(-2) s(-1), respectively, at [H2O] = 1.5 mol dm(-3) and [oxalic acid] = 10(-2) mol dm(-3). the constant ratio for reactions of the monomolecular decomposition of tert-butoxy radical (tert-BuO center dot -> CH3COCH3 + CH3) and its interaction with the CyH (tert-BuO center dot + CyH -> tert-BuOH + Cy-center dot) was calculated: 0.26 mol dm(-3). One of the reasons why oxalic acid accelerates the oxidation is due to the formation of an adduct between oxalic acid and 1 (K approximate to 10(3) mol(-1) dm(3)). Copyright (c) 2007 John Wiley & Sons, Ltd.
机译:含1,4,7-三甲基-1,4,7-三氮杂环壬烷和钴的双核锰(IV)配合物1在50摄氏度下用乙腈中的氢过氧化叔丁基过氧化氢(TBHP)氧化环己烷(CyH)的动力学已经研究了草酸催化的β-己内酰胺。已经表明,仅在配合物1与TBHP和草酸在水的存在下相互作用,才生成催化剂的活性形式(混合价二聚体'(MnMnIV)-Mn-III'。该活性形式的形成被认为是由于起始化合物1中Mn-O-Mn键的水解以及一个Mn-IV还原成Mn-III的缘故。引起CyH氧化的物质是自由基叔丁基。通过分解活性形式的单过氧衍生物而产生。测量了TBHP和1之间的平衡形成和中间加合物分解的常数:K = 7.4 mol(-1)dm(3)和k = 8.4 x 10(-2)s(-1) ,在[H 2 O] = 1.5mol dm(-3)和[草酸] = 10(-2)mol dm(-3)时。叔丁氧基自由基(叔BuO中心点-> CH3COCH3 + CH3)的单分子分解反应的恒定比率及其与CyH的相互作用(叔BuO中心点+ CyH->叔BuOH + Cy中心点) )计算为:0.26mol dm(-3)。草酸加速氧化的原因之一是由于草酸与1(K约等于10(3)mol(-1)dm(3))之间的加合物形成。版权所有(c)2007 John Wiley&Sons,Ltd.

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