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General solutions of sums of consecutive cubed integers equal to squared integers

机译:等于立方整数的连续立方整数之和的一般解

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All integer solutions (M, a, c) to the problem of the sums of NI consecutive cubed integers (a + i)(3) (a > 1, 0 <= i <= M 1) equaling squared integers c(2) are found by decomposing the product of the difference and sum of the triangular numbers of (a + M - 1) and (a - 1) in the product of their greatest common divisor g and remaining square factors delta(2) and sigma(2), yielding c = g delta sigma. Further, the condition that g must be integer for several particular and general cases yields generalized Pell equations whose solutions allow to find all integer solutions (M, a, c). showing that these solutions appear recurrently. In particular, it is found that there always exists at least one solution for the cases of all odd values of M, of all odd integer square values of a, and of all even values of M equal to twice an integer square. (C) 2015 Elsevier Inc. All rights reserved.
机译:NI个连续立方整数(a + i)(3)(a> 1,0 <= i <= M 1)等于平方整数c(2)的和的所有整数解(M,a,c)通过分解(a + M-1)和(a-1)的最大公除数g与剩余平方因子delta(2)和sigma(2)的乘积和三角数之和的乘积来找到),得出c = g三角积分。此外,对于几种特殊情况和一般情况,g必须为整数的条件会产生广义的Pell方程,其解允许找到所有整数解(M,a,c)。表明这些解决方案经常出现。特别地,发现对于M的所有奇数,a的所有奇数整数平方值以及M的所有偶数等于整数平方的两倍的情况,总是存在至少一种解决方案。 (C)2015 Elsevier Inc.保留所有权利。

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