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On the Mobius number of the subgroup lattice of the symmetric group

机译:关于对称群的子群格的Mobius数

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In this paper, a formula is given for the Mobius number mu( l, S-n) of the subgroup lattice of the symmetric group S-n. This formula involves the Mobius numbers of certain transitive subgroups of S-n. When n has at most two (not necessarily distinct) prime factors or n is a power of two. this formula is refined so that it involves only the Mobius numbers of certain primitive subgroups of S-n. Using the O'Nan-Scott Theorem. the classification of finite simple groups, and the refined formula. the exact value of mu(l, S-n) is determined when n is prime, twice a prime, or a power of two. For certain primes p, mu(l, S-2p) not equal (2p)/2. This result gives a negative answer to a question raised by Stanley. (C) 1997 Academic Press.
机译:在本文中,给出了对称群S-n的子群格的Mobius数mu(l,S-n)的公式。该公式涉及S-n某些传递子群的Mobius数。当n最多具有两个(不一定是不同的)素数,或者n为2的幂。此公式经过改进,因此仅涉及S-n某些原始子组的Mobius数。使用O'Nan-Scott定理。有限简单组的分类和精炼公式。当n为素数,素数的两倍或2的幂时,确定mu(l,S-n)的确切值。对于某些素数p, mu(l,S-2p)不等于(2p) / 2。这个结果对斯坦利提出的问题给出了否定的答案。 (C)1997学术出版社。

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