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首页> 外文期刊>Journal of Chemical and Engineering Data: the ACS Journal for Data >Phase Equilibrium in the System RbCl-NdCl3-HCl(13.26 %)-H2O at 298.15 K and Standard Molar Enthalpy of Formation of New Solid Phase Compound
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Phase Equilibrium in the System RbCl-NdCl3-HCl(13.26 %)-H2O at 298.15 K and Standard Molar Enthalpy of Formation of New Solid Phase Compound

机译:RbCl-NdCl3-HCl(13.26%)-H2O体系在298.15 K时的相平衡和形成新固相化合物的标准摩尔焓

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摘要

The solubility of the quaternary system RbCl-NdCl3-HCl(13.26 %)-H2O at 298.15 K was determined, and the corresponding equilibrium diagram was constructed. The quaternary system consists of three equilibrium solid phases, RbCl, RbNdCl4·4H2O (1:1 type), and NdCl3·6H2O. The new solid phase compound RbNdCl4·4H2O was found to be congruently soluble in the system. The compound RbNdCl4·4H2O was characterized by X-ray diffraction, X-ray diffraction single crystal structure analysis, thermogravimetry, and differential thermogravimetry. It belongs to an orthorhombic system, with space group P21212, a = 0.6986(6) nm, b = 1.1319(1) nm, c = 0.6665(6) nm, Dc = 2.795 g·cm~(-3), and Z = 2. The compound loses its crystal water by one step at (370 to 474) K. The standard molar enthalpy of solution of RbNdCl4·4H2O in deionized water was measured to be -(26.97 ± 0.24) kJ·mol~(-1) by heat conduction microcalorimetry. Its standard molar enthalpy of formation was calculated to be -(2732.3 ± 1.0) kJ·mol~(-1).
机译:确定了四元体系RbCl-NdCl3-HCl(13.26%)-H2O在298.15 K的溶解度,并绘制了相应的平衡图。四元体系由三个平衡固相RbCl,RbNdCl4·4H2O(1:1型)和NdCl3·6H2O组成。发现新的固相化合物RbNdCl4·4H2O在系统中完全可溶。通过X射线衍射,X射线衍射单晶结构分析,热重分析和差示热重分析对化合物RbNdCl 4·4H 2 O进行表征。它属于正交晶系,空间群为P21212,a = 0.6986(6)nm,b = 1.1319(1)nm,c = 0.6665(6)nm,Dc = 2.795 g·cm〜(-3),Z =2。该化合物在(370至474)K下失去一步的结晶水。RbNdCl4·4H2O在去离子水中的标准摩尔焓经测量为-(26.97±0.24)kJ·mol〜(-1 )通过导热微量热法。计算其标准摩尔生成焓为-(2732.3±1.0)kJ·mol〜(-1)。

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