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The complexity of assigning genotypes to people in a pedigree consistently

机译:一致地给家谱中的人分配基因型的复杂性

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摘要

We discuss the complexity of a combinatorial problem in the field of genetics, which we call Genotype ASsignability problem and abbreviate as GAS. A pair of genes at a position on a pair of chromosomes is called a genotype. GAS is defined as follows: “A pedigree is given and, for one of positions where genotypes are located in a set of pairs of chromosomes of a person, the genotypes at the position of some people in the pedigree are given. Is it possible to assign all other people (i.e., all of the people of which the genotypes are not given) genotypes for the position so as not to cause inconsistency in the heredity of genotypes at the position in the whole of the pedigree?” GAS can be used to compute, from the genotypes at the same position of some people in a pedigree, the genotypes that each person in the pedigree can possess at the position. Although many combinatorial problems have been studied so far, GAS seems not to have been done yet. Let m be the number of different genes in a pedigree and n that of people in the pedigree. We prove that GAS is NP-complete when m3 and that it can be solved in linear time O(n) when m=2.
机译:我们讨论了遗传学领域组合问题的复杂性,我们称其为基因型可分配性问题,简称GAS。一对染色体上某个位置的一对基因称为基因型。 GAS的定义如下:“给出谱系,并且对于一个基因型位于一个人的一对染色体对中的位置中的一个,给出了谱系中某些人所在位置的基因型。是否可以将所有其他人(即没有给出基因型的所有人)的基因型分配给该位置,以免在整个谱系中导致该基因型的遗传不一致?” GAS可用于根据谱系中某些人处于相同位置的基因型来计算谱系中每个人在该位置所具有的基因型。尽管到目前为止已经研究了许多组合问题,但GAS似乎尚未完成。令m为谱系中不同基因的数目,n为谱系中人的数目。我们证明,当m3时,GAS是NP完全的;当m = 2时,它可以在线性时间O(n)中求解。

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