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A note on well-generated Boolean algebras in models satisfying Martin's axiom

机译:关于满足马丁公理的模型中生成良好的布尔代数的注记

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A Boolean algebra B is well generated, if it has a well-founded sublattice L such that L generates B. Let B be a superatomic Boolean algebra. The rank of B (rk(B)) is defined to be the Cantor Bendixon rank of the Stone space X of B. For every i ≤ rk(B) let λ_i(B) be the number of isolated points in the i's Cantor Bendixon derivative of X. The cardinal sequence of B is defined as λ(B) :+ <λ_i(B):i ≤ rk(X)>. If aB-{0}, then the rank of a (rk(a)) is defined as the rank of the Boolean algebra Ba{bB:ba}. An element a ∈ B - {0} is a generalized atom (a ∈ At()B), if the last cardinal in the cardinal sequence of Ba is 1. Let a, b ∈ At(B). We denote aBb, if rk(a)=rk(b)=rk(a·b). A subset H is contained in At(b) is a complete set of representatives (CSR) for B, if for every there is a unique bH such that bBa. Any CSR for B generates B. We say that B is hereditarily decreasingly canonically well generated, if for every subalgebra C of B and every CSR H for C there is a CSR M for C such that: (1) for every aH and bM: if bCa then b ≤ a; (2) the sublattice of C generated by M is well founded. Theorem. Assume (MA + x_1 < 2~(x_0)). Let ε be a countable ordinal, κ < 2~(x_0) and n < ω. If B is a superatomic Boolean algebra such that λ(B) = <κ, x_1, n> or λ(B) = , then B is hereditarily decreasingly canonically well generated.
机译:如果布尔代数B具有充分成立的子格L,使得L生成B,则布尔代数B生成良好。令B为超原子布尔代数。 B的秩(rk(B))定义为B的石头空间X的Cantor Bendixon秩。对于每个i≤rk(B),令λ_i(B)是i的Cantor Bendixon中的孤立点数B的基序定义为λ(B):+ <λ_i(B):i≤rk(X)>。如果aB- {0},则将(rk(a))的秩定义为布尔代数Ba {bB:ba}的秩。如果Ba的基数序列中的最后一个基数为1,则元素a∈B-{0}是广义原子(a∈At()B)。令a,b∈At(B)。如果rk(a)= rk(b)= rk(a·b),则我们表示aBb。如果每个都有唯一的bH使得bBa,则At(b)中包含的子集H是B的完整代表(CSR)集。 B的任何CSR都会生成B。我们说B是遗传地递减地典范地良好生成的,如果对于B的每个子代数C和C的每个CSR H而言,C的CSR M都满足:(1)每个aH和bM:如果bCa,则b≤a; (2)由M生成的C的子格是成立的。定理。假设(MA + x_1 <2〜(x_0))。令ε为可数序数,κ<2〜(x_0)且n <ω。如果B是超原子布尔代数,使得λ(B)= <κ,x_1,n>或λ(B)= ,则B遗传地递减地规范地生成。

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