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BOUNDS FOR NONADAPTIVE GROUP TESTS TO ESTIMATE THE AMOUNT OF DEFECTIVES

机译:非适应性小组测试的界限,以估计缺陷的数量

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Group testing is the problem of finding d defectives in a set of n elements, by asking carefully chosen subsets (pools) whether they contain defectives. Strategies are preferred that use both a small number of tests close to the information-theoretic lower bound d log2 n, and a small constant number of stages, where tests in every stage are done in parallel, in order to save time. They should even work if d is not known in advance. In fact, one can succeed with O(d log n) queries in two stages, if certain tests are randomized and a constant failure probability is allowed. An essential ingredient of such strategies is to get an estimate of d within a constant factor. This problem is also interesting in its own right. It can be solved with O(log n) randomized group tests of a certain type. We prove that λ(log n) tests are also necessary, if elements for the pools are chosen independently. The proof builds upon an analysis of the influence of tests on the searcher's ability to distinguish between any two candidate numbers with a constant ratio. The next challenge is to get optimal constant factors in the O(log n) test number, depending on the prescribed error probability and the accuracy of d. We give practical methods to derive upper bound tradeoffs and conjecture that they are already close to optimal. One of them uses a linear programming formulation.
机译:组测试是通过询问精心选择的子集(池)是否包含缺陷来找到n个元素集中的d个缺陷的问题。最好使用既要进行接近于信息理论下界d log2 n的少量测试,又要使用不变数量的阶段(为了避免浪费时间,每个阶段中的并行测试)的策略。如果事先不知道d,它们甚至应该工作。实际上,如果某些测试是随机的并且允许恒定的失败概率,则可以在两个阶段中成功执行O(d log n)查询。这种策略的重要组成部分是在恒定因子内获得d的估计值。这个问题本身也很有趣。可以使用特定类型的O(log n)随机分组测试来解决。我们证明,如果独立选择池的元素,λ(log n)测试也是必要的。证明建立在对测试对搜索者区分具有恒定比率的两个候选数字的能力的影响的分析之上。下一个挑战是根据规定的错误概率和d的精度,在O(log n)测试数中获得最佳常数因子。我们给出实用的方法来得出上限折衷和推测,它们已经接近最优。其中之一使用线性编程公式。

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