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Theoretical study on the mechanism of H-2 activation mediated by two transition metal thiolate complexes: Homolytic for Ir, heterolytic for Rh

机译:两种过渡金属硫醇盐配合物介导的H-2活化机理的理论研究:Ir均溶,Rh杂溶

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The molecular mechanism of H-2 activation by two transition metal thiolate complexes [Cp*M(PMe3)(SDmp)](BAr4F) (M = Ir, Rh) (Ohki, Y; Sakamoto, M; Tatsumi, K. J. Am. Chem. Soc., 2008, 130, 11610-11611) has been investigated using density functional theory calculations. According to our calculations, the reaction of the iridium thiolate complex with H-2 is likely to proceed through the following steps: (1) the oxidative addition of H-2 to the iridium center to generate a dihydride intermediate; (2) the reductive elimination of one Ir-bound hydrogen to produce the hydride thiol product. For the rhodium thiolate complex, its reaction with H-2 is to form the dihydrogen intermediate first, and then the H-H bond is heterolytically cleaved at the Rh-S bond via a four-center transition state to yield the hydride thiol product. The rate-determining step is the oxidative addition step (with a barrier of 18.0 kcal/mol in the solvent) for the iridium complex, and the formation of the dihydrogen complex (with a barrier of 13.9 kcal/mol in the solvent) for the rhodium complex. The calculated free energy profiles for both metal thiolate complexes can reasonably account for the observed reversible H-2 activation by two metal thiolate complexes under mild conditions.
机译:两个过渡金属硫醇盐配合物[Cp * M(PMe3)(SDmp)](BAr4F)(M = Ir,Rh)(Ohki,Y; Sakamoto,M; Tatsumi,KJ Am.Chem)激活H-2的分子机制(Soc。,2008,130,11610-11611)已使用密度泛函理论计算进行了研究。根据我们的计算,硫氰酸铱络合物与H-2的反应可能通过以下步骤进行:(1)将H-2氧化加成到铱中心生成二酐中间体。 (2)还原消除一个与Ir结合的氢,生成氢化硫醇产物。对于硫醇铑配合物,其与H-2的反应是首先形成二氢中间体,然后通过四中心过渡态在Rh-S键处将H-H键杂化裂解,生成氢化硫醇产物。决定速率的步骤是铱络合物的氧化加成步骤(在溶剂中的势垒为18.0 kcal / mol)和二氢络合物的形成(溶剂中的势垒为13.9 kcal / mol)。铑配合物。两种金属硫醇盐配合物的计算出的自由能分布可以合理地解释在温和条件下观察到的两种金属硫醇盐配合物可逆的H-2活化。

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