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TRACING CERTAIN N-DIMENSIONAL SPACE POINTS

机译:跟踪某些N维空间点

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1. Introduction. Our motivation for this research is to describe an iterative sequence of n-dimensional points mathematically. Consider the famous Fibonacci sequence 1,2,3, 5,8,13,... with the relationship Fn = Fn-1 + Fn-2 for n > 1 and Fo = F1 = 1. By examination, we notice that every Fibonacci number Fn (n > 2) can be obtained from the previous ones iteratively. What about a set of n-dimensional points in the vector space Rn? How do we use a mathematical function to trace the points? For example, a set of 3-dimensional points is given by Pi = (1,2,3),P2 = (1,3,5), P3 = (2,5,8), P4 = (3,8,13), P5 = (5,13,21),.... An explicit formula for the points is given by Pk = (Fk, Fk+2, Fk+3) for i > 1. Similar to the Fibonacci sequence, we may describe this sequence of points by the relationship Pk = Pk-1+Pk-2 for k > 2 and the initial conditions P1 = (1,2,3),P2 = (1,3,5). Another approach is to use a 3-tuple linear function f = (χ2-χ1,2χ2-χ1,3χ2-χ1) to describe the sequence. One can easily check that f(1,2,3) = (1,3,5), f(1,3,5) = (2,5,8), f(2,5,8) = (3,8,13), and f(3,8,13) = (5,13,21). Iteratively, f(Pk) = Pk+1 for all k > 1. A natural question is, if S = {Ai,A2,..., Am+1} with Ai = (ai1,ai2,...,ain) ∈ Rn, can we find a multivariable function f: Rn →Rn such that f(Ai) = Ai+1 for all i = 1,2,..., m? If so can we construct a function satisfying certain constraints? In this paper, we focus on the construction of such tracing functions.
机译:1.简介。我们进行这项研究的动机是用数学方法描述n维点的迭代序列。考虑著名的斐波那契数列1,2,3,5,8,13,...,其中n> 1且Fo = F1 = 1,关系为Fn = Fn-1 + Fn-2。斐波那契数Fn(n> 2)可以迭代地从前面的数中获得。向量空间Rn中的一组n维点呢?我们如何使用数学函数来追踪点?例如,Pi =(1,2,3),P2 =(1,3,5),P3 =(2,5,8),P4 =(3,8, 13),P5 =(5,13,​​21),....对于i> 1,点的显式由Pk =(Fk,Fk + 2,Fk + 3)给出。类似于斐波那契数列,我们可以通过k> 2和初始条件P1 =(1,2,3),P2 =(1,3,5)的关系Pk = Pk-1 + Pk-2来描述点的序列。另一种方法是使用三元组线性函数f =(χ2-χ1,2χ2-χ1,3χ2-χ1)来描述序列。可以轻松检查f(1,2,3)=(1,3,5),f(1,3,5)=(2,5,8),f(2,5,8)=(3 ,8,13)和f(3,8,13)=(5,13,​​21)。迭代地,对于所有k> 1,f(Pk)= Pk + 1。一个自然的问题是,如果S = {Ai,A2,...,Am + 1}且Ai =(ai1,ai2,...,ain )∈Rn,我们能找到一个多元函数f:Rn→Rn使得对于所有i = 1,2,...,m的f(Ai)= Ai + 1吗?如果可以,我们可以构造一个满足某些约束的函数吗?在本文中,我们专注于此类跟踪函数的构造。

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