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Reprise of a 'Dense and Tense Story'

机译:重现“紧张与紧张的故事”

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摘要

Consider the following problem. Two uniform cubes have sides of length L. Cube 1 has volume mass density ρ_1 while cube 2 has density ρ_2 > ρ_1 Their average density, ρ = ρ_1 + ρ_2)/2, is equal to that of an incompressible fluid filling a beaker. The two cubes are glued together and fully immersed in the fluid with the lighter cube 1 positioned directly above cube 2, such that the interface between them is at depth H. Suppose that the glue has a density equal to that of the fluid, so that the combination of blocks and glue is overall neutrally buoyant in the fluid. Denote by F the maximum tensile force that the glue can withstand before tearing apart. Under what conditions will the cubes break apart (resulting in cube 1 rising to the surface and cube 2 sinking to the bottom)?
机译:考虑以下问题。两个均匀的立方体的边长为L。立方体1的体积质量密度为ρ_1,而立方体2的密度为ρ_2>ρ_1,其平均密度ρ=ρ_1+ρ_2)/ 2,等于填充烧杯的不可压缩流体的密度。将两个立方体胶合在一起,并将较轻的立方体1直接放置在立方体2上方,将其完全浸入流体中,以便它们之间的界面位于深度H处。假定胶的密度等于流体的密度,因此块和胶水的组合在流体中总体上是中性的。用F表示胶水在撕开之前可以承受的最大拉力。在什么条件下,立方体会破裂(导致立方体1上升到表面,而立方体2下降到底部)?

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