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On the number of frames in binary words

机译:关于二进制字的帧数

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A frame is a square uu, where u is an unbordered word. Let F(n) denote the maximum number of distinct frames in a binary word of length n. We count this number for small values of n and show that F(n) is at most [n/2] + 8 for all n and greater than 7n/30 - ∈ for any positive ∈ and infinitely many n. We also show that Fibonacci words, which are known to contain plenty of distinct squares, have only a few frames. Moreover, by modifying the Thue-Morse word, we prove that the minimum number of occurrences of frames in a word of length n is [n/2] - 2.
机译:框架是方形uu,其中u是无边界单词。令F(n)表示长度为n的二进制字中不同帧的最大数目。我们对n的较小值进行计数,结果表明,对于所有n,F(n)最多为[n / 2] + 8,对于任何正ε和无限多个n,F(n)均大于7n / 30-∈。我们还显示,斐波那契单词(已知包含大量不同的正方形)只有几个框架。此外,通过修改Thue-Morse单词,我们证明了长度为n的单词中出现的帧的最小数目为[n / 2]-2。

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