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Inequalities for Euler's constant

机译:欧拉常数的不等式

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Letγ_n =sum from k=1 to n of 1/k- log n and γ = lim γ_n.Robert M. Young [1] proved that 1/2n+2<γ_n-γ<1/2n.In a different context, I recently found a nice trick, which enables me to give a quick proof of (1), and indeed to improve on it. Rather than use the series for log (1 + x) with x =1 I shall use the formula with x =1+1. As you will see, it gives a series of positive terms. The advantage of having a series of positive terms is that it is relatively easy to estimate the sum, that is, to give upper and lower bounds for the sum.
机译:令γ_n=从k = 1到n / 1 / k-log n的和γ= limγ_n。RobertM. Young [1]证明1 / 2n + 2 <γ_n-γ<1 / 2n。我最近发现了一个不错的技巧,使我能够快速证明(1),并确实加以改进。与其使用x = 1 / n的log(1 + x)序列,不如使用x = 1 / n + 1的公式。如您所见,它给出了一系列积极的术语。具有一系列正项的优点在于,估计和是相对容易的,也就是说,给出和的上限和下限。

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