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Constructing tests to compare two proportions whose critical regions guarantee to be Barnard convex sets

机译:构造测试以比较两个关键区域保证为Barnard凸集的比例

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摘要

In both statistical non-inferiority (NI) and superiority (S) tests, the critical region must be a Barnard convex set for two main reasons. One, being computational in nature, based on the fact that calculating test sizes is a computationally intensive problem due to the presence of a nuisance parameter. However, this calculation is considerably reduced when the critical region is a Barnard convex set. The other reason is that in order for the NI/S statistical tests to make sense, its critical regions must be Barnard convex sets. While it is indeed possible for NI/S tests' critical regions to not be Barnard convex sets, for the reasons stated above, it is desirable that they are. Therefore, it is important to generate, from a given NI/S test, a test which guarantees that the critical regions are Barnard convex sets. We propose a method by which, from a given NI/S test, we construct another NI/S test, ensuring that the critical regions corresponding to the modified test are Barnard convex sets, we illustrate this through examples. This work is theoretical because the type of developments refers to the general framework of NI/S testing for two independent binomial proportions and it is applied because statistical tests that do not ensure that their critical regions are Barnard convex sets may appear in practice, particularly in the clinical trials area. (C) 2016 Elsevier B.V. All rights reserved.
机译:在统计非劣效性(NI)和优势(S)检验中,由于两个主要原因,关键区域必须是Barnard凸集。一种本质上是计算性的,是基于以下事实:由于存在讨厌的参数,因此计算测试大小是一个计算量大的问题。但是,当关键区域是Barnard凸集时,此计算将大大减少。另一个原因是,为了使NI / S统计检验有意义,其关键区域必须是Barnard凸集。尽管NI / S测试的关键区域确实有可能不是巴纳德凸集,但出于上述原因,还是希望它们是。因此,从给定的NI / S测试中生成保证关键区域为Barnard凸集的测试非常重要。我们提出一种方法,从给定的NI / S测试中构造另一个NI / S测试,以确保与修改后的测试相对应的关键区域是Barnard凸集,我们通过示例进行说明。这项工作是理论上的,因为开发的类型指的是针对两个独立的二项式比例进行NI / S测试的通用框架,并且之所以应用它是因为在实践中可能会出现无法确保其关键区域为巴纳德凸集的统计测试,尤其是在临床试验领域。 (C)2016 Elsevier B.V.保留所有权利。

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