...
首页> 外文期刊>Scientiae mathematicae Japonicae >Multi-round card game with arbitration and random amount of bet
【24h】

Multi-round card game with arbitration and random amount of bet

机译:带有仲裁和随机下注额的多回合纸牌游戏

获取原文
获取原文并翻译 | 示例
   

获取外文期刊封面封底 >>

       

摘要

We consider zero-sum game which is usually called poker. Each of two players (I and II) independently draws a number (x and y, respectively) according to uniform distribution in [0, 1]. Also they jointly draw a number z according to the distribution with cdf F(z), O < z < ∞. After observing this number and the "center card" z each player chooses either to accept (A) or to reject (R) his number. If both players choose A, showdown is made and I wins (loses) if x > (<) y, getting reward z(-z). If both players choose R, then the numbers are rejected and the game proceeds to the next round with the newly drawn numbers x', y', and z'. If players choose different choices, then arbitration comes in, and forces to take the same choices as I's (II's) with probability p (p-bar). Arbitration is fair (unfair) if p = (≠) 1/2. The game is played in n rounds. Player I (II) aims to maximize (minimize) the expected reward to I. Explicit solution is derived to this sequential game, and examples are shown for the cases where z obeys discrete and continuous uniform distributions.
机译:我们考虑零和游戏,通常称为扑克。根据[0,1]中的均匀分布,两个玩家(I和II)中的每一个都独立绘制一个数字(分别为x和y)。他们还根据cdf F(z)的分布共同绘制一个数字z,O (<)y,则我赢(输),得到奖励z(-z)。如果两个玩家都选择R,则数字将被拒绝,游戏将使用新绘制的数字x',y'和z'进入下一轮。如果玩家选择了不同的选择,那么仲裁就进入了,并以概率p(p-bar)强制选择与I(II)相同的选择。如果p =(≠)1/2,则仲裁是公平的(不公平的)。游戏进行n轮。玩家I(II)旨在最大化(最小化)对I的预期奖励。此顺序游戏得出了明确的解决方案,并给出了z服从离散和连续均匀分布的情况的示例。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号